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3 years ago

I need help on 9-11 please

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

5 0

Hello! I would love to help!

9. Basically, it is asking us to multiply 5.2 by 46.

5.2*46=239.2

So, your answer is 239.2 inches.

10. First, let's find out how many blocks she has left to run by subtracting the number of blocks she has already ran by the number of total blocks.

60-18=42

So Susan has 42 blocks left to run. Now, let's divide that by 2 since she can run 2 blocks per minute.

42/2=21

So, the answer is 21 minutes.

11. Let's set up an equation: We know that she will automatically pay $49.95 per month, plus $0.15 per additional minute. We also know her final total for the month was $61.20:

49.95+0.15m=61.20

Let's solve! Subtract both sides by 49.95

49.95+0.15m-49.95=61.20-49.95

Simplify

0.15m=11.25

Now, divide both sides by 0.15

0.15m/0.15=11.25/0.15

M=75

So your answer is 75 additional minutes.

Hope this helped! Comment if you have questions!

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Factor completely 3x3 − 6x2 − 24x. 3x(x − 4)(x + 2) 3x(x + 4)(x − 2) 3x(x − 3)(x − 2) 3x(x + 3)(x − 2)

inysia [295]

Answer:

3x(x - 4)(x + 2)

Step-by-step explanation:

Given

3x³ - 6x² - 24x ← factor out common factor of 3x from each term

= 3x(x² - 2x - 8) ← factor the quadratic

Consider the factors of the constant term (- 8) which sum to give the coefficient of the x- term.

The factors are - 4 and + 2, since

- 4 × 2 = - 8 and - 4 + 2 = - 2, thus

x² - 2x - 8 = (x - 4)(x + 2) and

3x³ - 6x² - 24x = 3x(x - 4)(x + 2)

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3 years ago

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago

Use long division to find the value of 1,875÷15.

SashulF [63]

Answer:

125

Step-by-step explanation:

1875 / 15 = 125

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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3 years ago

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svlad2 [7]

Answer:

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304/4 = 76

76 x 7.5 = 570

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2 years ago