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drek231 [11]
3 years ago
9

Which equation has no solution?​

Mathematics
1 answer:
lord [1]3 years ago
5 0

Answer:

Equation 5 + 2(3 + 2x) = x + 3(x + 1) has no solution.

Step-by-step explanation:

We are looking at two lines.

4(x + 3) + 2x = 6(x +2)

4x + 12 + 2x = 6x + 12

6x + 12 = 6x + 12

These are two identical lines, with an infinite number of solutions. (All points on the lines are the exactly the same).

5 + 2(3 + 2x) = x + 3(x + 1)

5 + 6 + 4x = x + 3x + 3

4x + 11 = 4x + 3

Both lines have the same gradient but have a different incline with the y axis. By definition, they are parallel to each other and there fore have zero solutions. Equation 5 + 2(3 + 2x) = x + 3(x + 1) has no solution, which is the answer we are looking for.

5(x + 3) + x = 4(x +3) + 3

5x + 15 + x = 4x + 12 + 3

6x + 15 = 4x + 15

These are two different lines with exactly one solution.

4 + 6(2 + x) = 2(3x + 8)

4 + 12 + 6x = 6x + 16

6x + 16 = 6x + 16

These are two identical lines, with an infinite number of solutions. (All points on the lines are the exactly the same).

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Answer:

8x - 36

Step-by-step explanation:

Use distributive property: a(b + c) = a*b + a*c

4(2x - 9)= 4*2x - 4*9

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If two segments are both parallel to a third line they must be:

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Rewrite as y−k=a(x−h)2 or x−h=a(y−k)2. Find the vertex, focus, and directrix.<br> y−3=(2−x)^2
Talja [164]

Given:

The given equation is

y-3=(2-x)^2

To find:

The vertex, focus, and directrix.

Solution:

The equation of a parabola is

y-k=a(x-h)^2     ...(i)

where, (h,k) is vertex, \left(h,k+\dfrac{1}{4a}\right) and directrix is y=k-\dfrac{1}{4a}

We have,

y-3=(2-x)^2

It can be written as

y-3=(-(x-2))^2

y-3=(x-2)^2    ...(ii)

On comparing (i) and (ii), we get

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Vertex of the parabola is (2,3).

Focus=\left(2,3+\dfrac{1}{4(1)}\right)

Focus=\left(2,3+\dfrac{1}{4}\right)

Focus=\left(2,\dfrac{13}{4}\right)

Therefore, the focus of the parabola is \left(2,\dfrac{13}{4}\right).

Directrix of the parabola is

y=3-\dfrac{1}{4(1)}

y=3-\dfrac{1}{4}

y=\dfrac{11}{4}

Therefore, the directrix of the parabola is y=\dfrac{11}{4}.

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If 5 equals 1

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