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drek231 [11]
2 years ago
9

Which equation has no solution?​

Mathematics
1 answer:
lord [1]2 years ago
5 0

Answer:

Equation 5 + 2(3 + 2x) = x + 3(x + 1) has no solution.

Step-by-step explanation:

We are looking at two lines.

4(x + 3) + 2x = 6(x +2)

4x + 12 + 2x = 6x + 12

6x + 12 = 6x + 12

These are two identical lines, with an infinite number of solutions. (All points on the lines are the exactly the same).

5 + 2(3 + 2x) = x + 3(x + 1)

5 + 6 + 4x = x + 3x + 3

4x + 11 = 4x + 3

Both lines have the same gradient but have a different incline with the y axis. By definition, they are parallel to each other and there fore have zero solutions. Equation 5 + 2(3 + 2x) = x + 3(x + 1) has no solution, which is the answer we are looking for.

5(x + 3) + x = 4(x +3) + 3

5x + 15 + x = 4x + 12 + 3

6x + 15 = 4x + 15

These are two different lines with exactly one solution.

4 + 6(2 + x) = 2(3x + 8)

4 + 12 + 6x = 6x + 16

6x + 16 = 6x + 16

These are two identical lines, with an infinite number of solutions. (All points on the lines are the exactly the same).

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Allisa [31]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
Which expression is equivalent to 64x^3-343
In-s [12.5K]

Answer:

B:  (4x - 7)(16x^2 + 28x + 49)

Step-by-step explanation:

64x^3-343 can be rewritten as 4^3x^3 - 7^3 or (4x)^3 - 7^3.  This is the difference of two cubes.  The appropriate formula for factoring such is

       a^3 - b^3 = (a - b)(a^2 + ab + b^2).  Therefore,

our (4x)^3 - 7^3 = (4x - 7)(16x^2 + 28x + 49).  This is Answer B.

4 0
3 years ago
What is the equation of the line that passes through (-5,6) and (3,-10)??
Tanzania [10]
The equation is -2x-4. u can use y2-y1/x2-x1.
7 0
3 years ago
Hello, Can someone please explain on how to do this? thank you!
Marrrta [24]
Steps:

1) determine the domain

2) determine the extreme limits of the function

3) determine critical points (where the derivative is zero)

4) determine the intercepts with the axis

5) do a table

6) put the data on a system of coordinates

7) graph: join the points with the best smooth curve

Solution:

1) domain

The logarithmic function is defined for positive real numbers, then you need to state x - 3 > 0

=> x > 3 <-------- domain

2) extreme limits of the function

Limit log (x - 3) when x → ∞ = ∞

Limit log (x - 3) when x → 3+ = - ∞ => the line x = 3 is a vertical asymptote

3) critical points

dy / dx = 0 => 1 / x - 3 which is never true, so there are not critical points (not relative maxima or minima)

4) determine the intercepts with the axis

x-intercept: y = 0 => log (x - 3) = 0 => x - 3 = 1 => x = 4

y-intercept: The function never intercepts the y-axis because x cannot not be 0.

5) do a table

 x                          y = log (x - 3)

limit x → 3+            - ∞

3.000000001        log (3.000000001 -3) = -9

3.0001                  log (3.0001 - 3) = - 4

3.1                       log (3.1 - 3) = - 1

4                          log (4 - 3) = 0

13                       log (13 - 3) = 1

103                     log (103 - 3) = 10

lim x → ∞             ∞

Now, with all that information you can graph the function: put the data on the coordinate system and join the points with a smooth curve.
7 0
3 years ago
Read 2 more answers
Some help me with this math problem
Anestetic [448]
Only the upper-left statement is NOT true.
5 0
3 years ago
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