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3 years ago

Why did one-half of the Moon's surface remain

Physics

1 answer:

choli [55]3 years ago

6 0

Answer:

The moon's revolution around its axis and the moon's revolution around the Earth take the same time, approximately 27 days. That causes one side of the Moon to always face the Earth while the other side always faces away from the Earth. That is why it took probes to go into space to photograph the side that is never visible from Earth for people to be able to see it.

You might be interested in

Metamorphic rocks are commonly formed at what kind of plate boundary?

DerKrebs [107]

the answer is near the divergent plate boundary i think

5 0

4 years ago

A marble, a bowling ball, a basketball, and a baseball are all sitting on the top shelf of a display case. Which one has the gre

Katena32 [7]

Answer:

Bowling Ball

Explanation:

The potential energy depends on the factors: mass of the object and distance between the two objects. In this case the distance is between the ground and the balls. Here, the bowling ball is heaviest and its center of mass is farthest in comparison to other two balls. Thus, it has the greatest potential energy.

5 0

3 years ago

Show your work please

nekit [7.7K]

Answer:

$V = U + at$

Explanation:

Given the following data;

Initial velocity = 0 (since the stone is starting from rest).

Final velocity = 32 m/s

Acceleration = g = 10 m/s²

Time = 3.2 seconds

To show that the speed of the stone when it hits the ground is 32 m/s, we would use the first equation of motion;

$V = U + at$

Where;

V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.

Substituting into the formula, we have;

$32 = 0 + 10*3.2$

$32 = 0 + 32$

$32 = 32$

Proven: 32 m/s = 32 m/s

7 0

3 years ago

An oxygen sensor is being tested with a digital multimeter using the MIN/MAX function. The readings are: minimum = 78 mV; maximu

vovikov84 [41]

Answer:

Technician A

Explanation:

An oxygen sensor is being tested with a digital multimeter using the MIN/MAX function. The readings are: minimum = 78 mV; maximum = 932 mV; average = 442 mV. Technician A says that the engine is operating normally. Technician B says that the oxygen sensor is skewed too rich. Which technician is correct?

an oxygen sensor detects te amount of oyen in an engine at the exhaust pipe.

if the oxygen sensor detects oxygen at the above boundary condition, ten the engine is in good working condition

6 0

3 years ago

Point charges q1=50μCq1=50μC and q2=−25μCq2=−25μC are placed 1.0 m apart. (a) What is the electric field at a point midway betwe

avanturin [10]

Answer:

a) E = 2.7x10⁶ N/C

b) F = 54 N

Explanation:

a) The electric field can be calculated as follows:

$E = \frac{Kq}{d^{2}}$

Where:

K: is the Coulomb's constant = 9x10⁹ N*m²/C²

q: is the charge

d: is the distance

Now, we need to find the electric field due to charge 1:

$E_{1} = \frac{9 \cdot 10^{9} N*m^{2}/C^{2}*50 \cdot 10^{-6} C}{(0.5 m)^{2}} = 1.8 \cdot 10^{6} N/C$

The electric field due to charge 2 is:

$E_{2} = \frac{9 \cdot 10^{9} N*m^{2}/C^{2}*(-25) \cdot 10^{-6} C}{(0.5 m)^{2}} = -9.0 \cdot 10^{5} N/C$

The electric field at a point midway between them is given by the sum of E₁ and E₂ (they are in the same direction, that is to say, to the right side):

$E_{T} = E_{1} + E_{2} = 1.8 \cdot 10^{6} N/C + 9.0 \cdot 10^{5} N/C = 2.7 \cdot 10^{6} N/C to the right side$

Hence, the electric field at a point midway between them is 2.7x10⁶ N/C to the right side.

b) The force on a charge q₃ situated there is given by:

$E_{T} = \frac{F_{T}}{q_{3}} \rightarrow F_{T} = E_{T}*q_{3}$

$F = 2.7 \cdot 10^{6} N/C*20 \cdot 10^{-6} C = 54 N$

Therefore, the force on a charge q₃ situated there is 54 N.

I hope it helps you!

3 0

3 years ago