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2 years ago

Identify the normal force on the shopping cart after 75 newtons of groceries are added to the cart

Physics

2 answers:

fgiga [73]2 years ago

7 0

Answer:

75 N upwards

Explanation:

The weight of the groceries acting vertically downward.

It works as teh action force acting on the ground.

Now according to the Newton's third law, for every action there is an equal and opposite reaction.

So, the reaction on the cart is same in magnitude but opposite in direction.

Action = weight of the groceries = 75 N acting downward

Reaction = Action but the direction is opposite

Normal reaction = 75 N upwards

Anna71 [15]2 years ago

3 0

If the shopping cart is parallel to the ground, the weight is acting vertically downward, then force is equal to weight. The normal force will be acting perpendicular to the ground,and acting upward opposite of the weight.

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The vehicles are fitted with shockers why

MissTica

Shockers acts as a shock absorber in the vehicle making the ride comfortable. When vehicle goes on rough road then it gets shocks from the road deformities the springs present in the shockers provide counter force and thus making the vehicle stable ride without shock.

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2 years ago

A bomb of mass 4 kg, initially at rest, explodes breaking into two fragments of 1 kg and 3 kg. Which one of the following statem

Kazeer [188]

Answer: The 1 kg fragment will have three times the speed of the 3kg fragment.

Explanation:Here for the bomb, its chemical energy gets converted into the mechanical energy.

According to the law of conservation of momentum, the two bodies will have equal momentum and to satisfy this condition the lighter mass will have the higher velocity.

∵ momentum, p = mass × velocity

∴The 1 kg fragment will have three times the speed of the 3kg fragment.

6 0

3 years ago

Show that the electric potential along the axis of a uniformly charged disk of radius R and charge density sigma is given by by

OlgaM077 [116]

Explanation:

Area of ring $\ 2{\pi} a d a$

Charge of on ring $d q=-(\ 2{\pi} a d a)$

Charge on disk

$Q=-\left(\pi R^{2}\right)$

$\begin{aligned}d v &=\frac{k d q}{\sqrt{x^{2}+a^{2}}} \\&=2 \pi-k \frac{a d a}{\sqrt{x^{2}+a^{2}}} \\v(1) &=2 \pi c k \int_{0}^{R} \frac{a d a}{\sqrt{x^{2}+a^{2}}} \cdot_{2 \varepsilon_{0}}^{2} R \\&=2 \pi \sigma k[\sqrt{x^{2}+a^{2}}]_{0}^{2} \\&=\frac{2 \pi \sigma}{4 \pi \varepsilon_{0}}[\sqrt{z^{2}+R^{2}}-(21)] \\&=\frac{\sigma}{2}(\sqrt{2^{2}+R^{2}}-2)\end{aligned}$

Note: Refer the image attached

8 0

3 years ago

A 47 kg mass is moving across a horizontal surface at 8 m/s. What is the force required to bring the mass to a stop in 4.1 secon

crimeas [40]

Answer:

Force = -91.7 Newton

Explanation:

Given the following data;

Mass = 47 kg

Time = 4.1 seconds

Initial velocity = 8 m/s

Since the object comes to a stop, its final velocity would be equal to zero.

To find the force required to bring it to stop;

First of all, we would determine the acceleration of the object;

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Substituting into the equation;

$a = \frac{0 - 8}{4.1}$

$a = \frac{-8}{4.1}$

Acceleration, a = -1.95 m/s²

Next, we would determine the force required to bring the object to stop;

$Force = mass * acceleration$

$Force = 47 * -1.95$

Force = -91.65 ≈ 91.7 Newton

6 0

3 years ago

HELP Please Hurry

nlexa [21]

The correct answers are:

A plane landing on an aircraft carrier.

Rain sticking to a window.

Two train cars coupling together.

2. The total momentum is zero.

3. 3.6 (kg*m/s) (Option C)

Explanations:

1) In simple terms (not a textbook definition), perfectly inelastic collision is a collision in which two bodies stick together (or becomes one) after a collision. Now let us have a look at the options:

A baseball bouncing off a bat: After collision, the ball and the bat do not stick to one another; therefore, it is NOT a perfectly inelastic collision.

Bumper cars bumping off of each other: After collision, cars bump off of each other, making their collision elastic, not perfectly inelastic collision.

A cue ball hitting an eight ball and stopping: After collision, although the cue ball stops, but all of its momentum will be transferred to the eight ball; and eight ball will start moving, where is cue ball stops. Not a perfectly inelastic collision.

A plane landing on an aircraft carrier: After plan lands, the plane and the aircraft carrier will be incontent with each other; making their collision perfectly inelastic.

Rain sticking to a window: Rain drop sticking to a window means both stick together after a collision, making it a perfectly inelastic collision.

Two train cars coupling together: Again both cars are sticking together, making it a perfectly inelastic collision.

Hence the correct answers are:

A plane landing on an aircraft carrier.

Rain sticking to a window.

Two train cars coupling together

7) Always remember that in a closed system, the total momentum is conserved, meaning:

Total initial momentum = Total final momentum

Initially, bodies are at rest, the total initial momentum (mv) is zero (since (m+2m)*0 = 0; as v = 0). As it is the closed system, the total final momentum will be equal to the total initial momentum. As the total initial momentum is zero, the total final momentum will also be zero.

Hence the correct answer is: The total momentum is zero.

3) As you can see in the table, the initial momentum of each and every entry is equal to the final momentum. In the case of X, as the final momentum is 3.6 kg*m/s, the initial momentum will be same as the final momentum (by considering the pattern in the table); therefore X (the initial momentum) will be 3.6 kg*m/s.

Hence the correct answer is: X = 3.6 (Option C)

6 0

2 years ago

Read 2 more answers