Answer:
The second ball moves with 0.83 m/s forward.
Explanation:
Given;
mass of the first ball, m₁ = 3 kg
initial velocity of the first ball, u₁ = 5 m/s
final velocity of the first ball, v₁ = 2.5 m/s
mass of the second ball, m₂ = 9kg
initial velocity of the second ball, u₂ = 0
final velocity of the second ball, v₂ = ?
From the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(3x5) + (9x0) = (3x2.5) + (9v₂)
15 = 7.5 + 9v₂
15 - 7.5 = 9v₂
9v₂ = 7.5
v₂ = 7.5/9
v₂ = 0.83 m/s
The second ball moves with 0.83 m/s forward.
The correct answers are:
(1) Force on the object.
(2) 4000 N
Explanations:
(1) According to Newton's second law, force (F) is directly proportional to the acceleration (a) of an object:
F ∝ a
(or F = ma)
As the force (F) on the object increases, the acceleration of that object will also increase. One thing to remember here is that the (net) force must be in the same direction as the acceleration produced by that force to get the maximum increase in the object's acceleration.
Hence, the correct answer is "force on the object."
(2) Again, by using Newton's second law, we can find the net force as follows:
Mass = m = 2000kg
acceleration = a = 2 m/s^2
Since,
F = ma --- (A)
Plug in the values in equation (A):
F = 2000 * 2 = 4000 N
Hence, the correct answer is 4000N.
Natural frequency is a frequency
when an object hits a s surface and causes ripples or vibrations or disturbance
of their nearby source. An example is throwing a stone to water. When you throw
a stone, it creates a wave around the fallen stone. The water is being
disturbed by the stone and creates a wave. This is a natural frequency.
Answer:
lamda=10.5m
Explanation:
using the equation of progressive wave.
y=Asin(wt-kx)
comparing the two equations together, we have
kx=0.6x , k=0.6
k=2π/λ
0.6=2*3.142/λ
cross multiply
0.6λ=6.284
divide both sides by 0.6
λ=6.284/0.6
λ=10.47m
approximate
λ=10.5m
U is correct on the first one
