The probability according to the given scenario is:
(a) <em>0.0395</em>
(b) <em>0.95</em>
(c) <em>0.076</em>
The given values are:
(a)
The probability that the b/w has tuberculosis as well as having (+) test will be:
→ 
By substituting the values, we get
→ 
→ 
(b)
The probability that a person does not have tuberculosis will be:
→ 
→ 
→ 
(c)
The person does not have tuberculosis as well as have a (+) test, the probability will be:
→ 
→ 
→ 
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Answer:
$2.7
Step-by-step explanation:
Let the price of one apple be x
and the price of one orange y
Hence ;
One apple and 3 oranges would cost:
x + 3×y = $5.10----------------------------(1)
One apple and 5 oranges would cost;
x + 5×y = $7.50--------------------------(2)
Subtracting eqn (1) from (2), we have :
x-x + 5y -3y = 7.5- 5.1
2y = 2.4
y = $1.2
From eqn(1)
x + 3y = $5.10
x= $5.10-3($1.2) = $5.10-$3.6 = $1.5
Hence x=$1.5 and y= $1.2
We are required to find the cost of one apple and one orange, hence :
x+y = $1.5+$1.2= $2.7
Answer:
B
Step-by-step explanation:
You are given two sides and the included angle, so you need to use the law of cosines.
c² = a² + b² - 2ab cos C
c² = 12² + 13² - 2(12)(13)cos 134°
c² = 313 - 312(-0.6947)
c² = 529.733
c = 23.016
Now use the law of sines.
c/sin C = a/sin A
23.016/sin 134° = 12/sin A
sin A = 12 × sin 134° / 23.016
sin A = 0.37504
A = 22.03°
B = 180° - 134° - 22.03°
B = 23.97°
m<A = 22°; m<B = 24°; c = 23 km
Answer: B
Answer:
First day: $75
Second day: $107
Together: $182
Step-by-step explanation:
First day:
$60 + $15 = $75
Second day:
$95 + $12 = $107
Together: $182
Answer:
Step-by-step explanation:
25π/18 * 180/π= 250°
