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adoni [48]
3 years ago
5

Can someone plss help me (middle school 7th grade) I dont this ​

Mathematics
1 answer:
AVprozaik [17]3 years ago
4 0

Answer:

what is it over?

Step-by-step explanation:

you have to be more specific

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Find f such that the given conditions are satisfiedf’(x)=x-4, f(2)=-1
kicyunya [14]

Given:

f^{\prime}\left(x\right)=x-4,\text{ and}f\left(2\right)=-1

To find:

The correct function.

Explanation:

Let us consider the function given in option D.

f(x)=\frac{x^2}{2}-4x+5

Differentiating with respect to x we get,

\begin{gathered} f^{\prime}(x)=\frac{2x}{2}-4 \\ f^{\prime}(x)=x-4 \end{gathered}

Substituting x = 2 in the function f(x), we get

\begin{gathered} f(2)=\frac{2^2}{2}-4(2)+5 \\ =2-8+5 \\ =-6+5 \\ f(2)=-1 \end{gathered}

Therefore, the given conditions are satisfied.

So, the function is,

f(x)=\frac{x^{2}}{2}-4x+5

Final answer: Option D

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A campfire burn 2 1/2 pounds of wood per hour. how many pounds of wood do you need to keep the camp firing burning for 6 hours?
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What is 32.7 times 10
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Determine the number of terms n in each geometric series.<br> 13) a1 = 0.75, r = 4, Sn =1023.75
Gnom [1K]

Answer:

Number of terms: n=6

Step-by-step explanation:

We are given:

a₁ = 0.75

r = 4

Sₙ = 1023.75

We need to find number of terms i.e n

The formula used will be:S_n=\frac{a(r^n-1)}{r-1}

Putting values and fining n

S_n=\frac{a(r^n-1)}{r-1}\\1023.75=\frac{0.75(4^n-1)}{4-1}\\ 1023.75=\frac{0.75(4^n-1)}{3}\\3\times 1023.75=0.75(4^n-1)\\3071.25=0.75(4^n-1)\\4^n-1=\frac{3071.25}{0.75}\\4^n-1=4095\\4^n=4095+1\\4^n=4096

We know that 4^6= 4096

4^n=4^6

Using Exponent rule: a^n=a^b => n=b

n=6

So, Number of terms: n=6

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