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Kruka [31]
4 years ago
9

When subtracting 8.7 from a certain number, the result is 22.95, as seen below. What number should go in the box to complete the

subtraction problem? The decimal 8.7 is subtracted from an unknown whole number to get 22.95. The unknown whole number has 3 in the tens place, an unknown number in the ones place, 6 in the tenths place, and 5 in the hundredths place.When subtracting 8.7 from a certain number, the result is 22.95, as seen below. What number should go in the box to complete the subtraction problem?
Mathematics
1 answer:
Anton [14]4 years ago
8 0
31.65 should go into the box to complete the subtraction problem.
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The volume of a rectangular box with a square base remains constant at 500 cm3 as the area of the base increases at a rate of 10
serious [3.7K]

Answer:

The rate of change of the height of the box at which is decreasing is \frac{5000}{130321} centimeters per second.

Step-by-step explanation:

From Geometry the volume of a rectangular box (V), measured in cubic centimeters, with a square base is modelled by the following formula:

V = A_{b}\cdot h (Eq. 1)

Where:

A_{b} - Area of the base, measured in square centimeters.

h - Height of the box, measured in centimeters.

The height of the box is cleared within the formula:

h = \frac{V}{A_{b}}

If we know that V = 500\,cm^{3} and A_{b} = 361\,cm^{2}, then the current height of the box is:

h = \frac{500\,cm^{3}}{361\,cm^{2}}

h = \frac{500}{361}\,cm

The rate of change of volume in time (\frac{dV}{dt}), measured in cubic centimeters per second, is derived from (Eq. 1):

\frac{dV}{dt} = \frac{dA_{b}}{dt}\cdot h + A_{b}\cdot \frac{dh}{dt} (Eq. 2)

Where:

\frac{dA_{b}}{dt} - Rate of change of the area of the base in time, measured in square centimeters per second.

\frac{dh}{dt} - Rate of change of height in time, measured in centimeters per second.

If we get that \frac{dV}{dt} = 0\,\frac{cm^{3}}{s}, \frac{dA_{s}}{dt} = 10\,\frac{cm^{2}}{s}, h = \frac{500}{361}\,cm and A_{b} = 361\,cm^{2}, then the equation above is reduced into this form:

0\,\frac{cm^{3}}{s} = \left(10\,\frac{cm^{2}}{s} \right)\cdot \left(\frac{500}{361}\,cm \right)+(361\,cm^{2})\cdot \frac{dh}{dt}

Then, the rate of change of the height of the box at which is decreasing is:

\frac{dh}{dt} = -\frac{5000}{130321}\,\frac{cm}{s}

The rate of change of the height of the box at which is decreasing is \frac{5000}{130321} centimeters per second.

5 0
3 years ago
How i can answer this question, NO LINKS, if you answer correctly i will give u brainliest!
mel-nik [20]

Answer:

The answer is 8

x=3

4^3/2^3=8

6 0
3 years ago
Help me plzzzzzzzzzz
marin [14]

Answer:

what is it?

Step-by-step explanation:

simply,subtract,find the domain,factor,

or write it in standard form.

3 0
4 years ago
Read 2 more answers
I need help Write and expression equivalent to 1/4a-3​
Blizzard [7]

Answer:

Combine any like terms on each side of the equation: x-terms with x-terms and constants with constants. Arrange the terms in the same order, usually x-term before constants. If all of the terms in the two expressions are identical, then the two expressions are equivalent.

Step-by-step explanation:

6 0
3 years ago
How many times can 6 go into 563
kirza4 [7]
You're going to get a long decimal. Just divide 563 by 6, and you'll get about 93.83333333...
6 0
3 years ago
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