Hello friend,here is the solution
<span>Let x be the total distance </span>
<span>Distance travelled by rail = 3/5 x </span>
Distance travelled by taxi = 1/4 x
<span>Distance travelled by bus = 1/8 x </span>
<span>The equation we obtain is </span>
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<span>x = 3/5 x + 1/4 x + 1/8 x +2 </span>
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<span>hope this solution helps you......</span>
I don’t know I suck at math sadly
Answer:
15 is your number and is a factor of 5 between 10 and 10
Answer:
ABQ = 139
BCR is the same as QBC since they are alternate interior angles
BCR = 41
Step-by-step explanation:
CBQ and SCB are same side interior angles so they add to 180
2a-9 + 5a +14 = 180
Combine like terms
7a +5 = 180
Subtract 5 from each side
7a = 175
Divide by 7
7a/7 = 175/7
a = 25
ABQ is the same as SCB since they are corresponding angles so
ABQ = SCB = 5a+14 = 5*25+14 = 125+14 = 139
BCR is the same as QBC since they are alternate interior angles
BCR = QBC = 2a-9 = 2*25 -9 = 50-9 = 41
