Answer:
a) e probability that a randomly selected baseball has a weight greater than 5.14 ounces
=P(X>5.14) =(b-x)/(b-a) =(5.155-5.14)/(5.155-5.085)=0.2143
b)
probability that a randomly selected baseball has a circumference less than 9.03 inches
=P(X<9.03) =(x-a)/(b-a) =(9.03-9)/(9.1-9)=0.3
c) probability that a randomly selected baseball will have a weight between 5.11 and 5.13 ounces and a circumference between 9.04 and 9.06 inches
=((5.13-5.11)/(5.155-5.085))*((9.06-9.04)/(9.1-9.0))=0.0571
Answer:
i have no clue
Step-by-step explanation:
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Answer:
<h3><u>Here</u><u> </u><u>in</u><u> </u><u>diagram</u><u> </u></h3>
- this is a Right angled triangle
- where
- hypontenuse =h=52
- Base=b=48
We need to find
According to Pythagorean theory







Answer:
what problem
Step-by-step explanation:
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For 12 divided by 587, I got 0.02044293.
For 587 divided by 12, I got 48.9166666666666.
I hope this helps.