Answer:
The balanced half reaction in an acidic medium is :
Explanation:
While balancing the half-reaction in an acidic medium, we will first balance oxygen atoms by adding water:
1) Adding 1 water molecule on product side to balance oxygen atoms.
Now balance hydrogen atom by adding 
.
2) Adding 2 hydrogen ions on reactant side to balance hydrogen atoms.
Now balance the charge adding electrons on the side where positive charge is mor.
3) Adding 1 electrons on reactant side to balance charge of the overall reaction:
The balanced half reaction in an acidic medium is :
The role of the salt bridge is to assure the neutrality of both compartments.
Explanation:
The formula mass of a molecule (also known as formula weight) is the sum of the atomic weights of the atoms in the empirical formula of the compound.
a. NO2
N = 14
O = 16
NO2 = 14 + (16 * 2) = 46 amu
b. C4H10
Empirical formular = C2H5
C = 12
H = 1
C2H5 = (12*1) + (1*5) = 12 + 5 = 17 amu
c. C6H12O6
Empirical formular = CH2O
C = 12
H = 1
O = 16
C2H5 = 12 + (1*2) + 16 = 30 amu
d MgBr2
Mg = 24
Br = 80
MgBr2 = 24 + (80*2) = 184 amu
e. HNO2
H = 1
N= 14
0 = 16
HNO2 = 1 + 14 + (16*2) = 47 amu
f. CBr4
C= 12
Br = 80
CBr4 = 12 + (80*4) = 332 amu
g. Cr(NO3)3
Cr = 52
N = 14
O = 16
Cr(NO3)3 = 52 + 3[14 + (3*16)] = 238 amu
Mass of CH₄ is 10.591 g.
The molar mass is a crucial characteristic of the material that is independent of sample size. The coherent unit of molar mass in the International System of Units (SI) is kg/mol. However, molar masses are usually generally given in g/mol due to historical considerations.
A chemical compound's molar mass is calculated by dividing its mass by the number of moles of the substance that make up the sample.
Δg = 587.9 KJ
CH₄ Molar mass = 16.05 g/mol
mol CH₄ = Δg / ΔH°
= 587.9 / 890.3 KJ/ mol
= 0.6603 mol CH₄
Mass CH₄ = 0.6603 × 16.05 g/mol
= 10.591 g
Therefore, the mass of CH₄ is 10.591 g.
Learn more about molar mass here:
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Answer:
43.868 J
Explanation:
Kinetic energy of a body is the amount of energy possessed by a moving body. The SI unit of kinetic energy is the joule (kg⋅m²⋅s⁻²).
According to classical mechanics, kinetic energy = 1/2 m·v²
Where, m= mass in kg and v= velocity in m/s
Given: m = 19.2 lb and v = 7.10 miles/h
Since, 1 lb= 0.453592 kg
∴ m = 19.2 lb = 19.2 × 0.453592 kg = 8.709 kg
Also, 1 mi = 1609.34 m and 1 h = 3600 sec
∴ v = 7.10 mi/h = 7.10 × 1609.34 m ÷ 3600 sec = 3.174 m/sec
Therefore, <u>kinetic energy of the goose</u> = 1/2 m·v² = 1/2 × (8.709 kg)× (3.174 m/sec)² = 43.868 J
