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3 years ago

Does pure water conduct electricity? if not, what can we do to make it conducting?

Chemistry

1 answer:

Anika [276]3 years ago

7 0

Explanation:

Pure water does not conduct electricity. This is because pure water do not contain any salts. Pure water can conduct electricity when common salt is added to it, as salt solution is conducting in nature.

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Is air a conductor or insulator

maksim [4K]

Insulator! I hope this helps! Pls mark mine the brainliest;)

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4 years ago

Read 2 more answers

When c2h4 molecules polymerize, the name of the polymer formed is

Gnoma [55]

<span>When c2h4 molecules polymerize, the name of the polymer formed is (b) Polyethylene. This is because the compound C2H4 is ethylene (common name) or ethene (IUPAC name) and polymerizing it would produce polyethylene. The other names are not applicable for C2H4.

</span>

7 0

3 years ago

What is the answer if u know please answer

forsale [732]

An atom having 52 protons and 54 electrons would have an atomic number of 52 and a net charge of -2. This element would be 52 Te 2-, or choice A.

7 0

4 years ago

Ethene is converted to ethane by the reaction flows into a catalytic reactor at 25.0 atm and 250.°C with a flow rate of 1050. L/

Sphinxa [80]

Answer : The percent yield of the reaction is, 76.34 %

Explanation : Given,

Pressure of $C_2H_4$ and $H_2$ = 25.0 atm

Temperature of $C_2H_4$ and $H_2$ = $250^oC=273+250=523K$

Volume of $C_2H_4$ = 1050 L per min

Volume of $H_2$ = 1550 L per min

R = gas constant = 0.0821 L.atm/mole.K

Molar mass of $C_2H_6$ = 30 g/mole

First we have to calculate the moles of $C_2H_4$ and $H_2$ by using ideal gas equation.

For $C_2H_4$ :

$PV=nRT\\\\n=\frac{PV}{RT}$

$n=\frac{PV}{RT}=\frac{(25atm)\times (1050L)}{(0.0821L.atm/mole.K)\times (523K)}$

$n=611.34moles$

For $H_2$ :

$PV=nRT\\\\n=\frac{PV}{RT}$

$n=\frac{PV}{RT}=\frac{(25atm)\times (1550L)}{(0.0821L.atm/mole.K)\times (523K)}$

$n=902.46moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$C_2H_4+H_2\rightarrow C_2H_6$

From the balanced reaction we conclude that

As, 1 mole of $C_2H_4$ react with 1 mole of $H_2$

So, 611.34 mole of $C_2H_4$ react with 611.34 mole of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $C_2H_4$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $C_2H_6$ .

As, 1 mole of $C_2H_4$ react to give 1 mole of $C_2H_6$

As, 611.34 mole of $C_2H_4$ react to give 611.34 mole of $C_2H_6$

Now we have to calculate the mass of $C_2H_6$ .

$\text{Mass of }C_2H_6=\text{Moles of }C_2H_6\times \text{Molar mass of }C_2H_6$

$\text{Mass of }C_2H_6=(611.34mole)\times (30g/mole)=18340.2g$

The theoretical yield of $C_2H_6$ = 18340.2 g

The actual yield of $C_2H_6$ = 14.0 kg = 14000 g (1 kg = 1000 g)

Now we have to calculate the percent yield of $C_2H_6$

$\%\text{ yield of }C_2H_6=\frac{\text{Actual yield of }C_2H_6}{\text{Theoretical yield of }C_2H_6}\times 100=\frac{14000g}{18340.2g}\times 100=76.34\%$

Therefore, the percent yield of the reaction is, 76.34 %

5 0

4 years ago

You have a sample of 75.6 g of C3H8. How many moles of C3H8 are in the sample?

dsp73

The number of moles that are contained in the given mass of propane ( $C_3H_8$ is 1.7143 moles.

<u>Given the following data:</u>

Mass of propane = 75.6 grams.

<u>Scientific data:</u>

The molar mass of propane = 44.1 g/mol.

To calculate the number of moles that are contained in the given mass of propane ( $C_3H_8$ ):

<h3>How to calculate the moles of a compound.</h3>

In this exercise, you're required to determine the number of moles of propane that are contained in the given sample:

Mathematically, the number of moles contained in a chemical compound is given by this formula:

$Number\;of\;moles = \frac{mass}{molar\;mass}$

Substituting the given parameters into the formula, we have;

$Number\;of\;moles = \frac{75.6}{44.1}$

Number of moles = 1.7143 moles.

Read more on number of moles here: brainly.com/question/3173452

3 0

3 years ago

Does pure water conduct electricity? if not, what can we do to make it conducting?​

Does pure water conduct electricity? if not, what can we do to make it conducting?