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Ivahew [28]
3 years ago
9

Which graph represents y as a function of x. i will mark branlist

Mathematics
1 answer:
allsm [11]3 years ago
3 0

Answer:

The very first graph is your answer

Step-by-step explanation:

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Consider the recursively defined set S: Basis Step: The unit circle is in S. Recursive Step: if x is in S, then x with a line th
Schach [20]

Answer:

Check the explanation

Step-by-step explanation:

Kindly check the attached images for the step by step explanation to the question

7 0
2 years ago
Drag each interval to a box to show if the function shown is increasing, decreasing or neither over that interval
Stolb23 [73]

Answer:

6 < x < 8 is decreasing

10 < x < 14 is neither

8 < x < 10 is increasing

4 < x < 6 is increasing

1 < x < 4 is decreasing

Step-by-step explanation:

just see where the line is going up or down

down is decreasing

up is increasing

6 0
2 years ago
Find the number of distinguishable permutations of the letters m, i, s, s, i, s, s, i, p, p, i.
Tatiana [17]

Solution:

we have been asked to find the number of distinguishable permutations of the letters m, i, s, s, i, s, s, i, p, p, i.

Here we can see

m appears 1 time.

i appears 4 times.

S appears 4 times.

p appears 2 times.

Total number of letters are 11.

we will divide the permutation of total number of letters by the permutation of the number of each kind of letters.

The number of distinguishable permutations=\frac{11!}{1!2!4!4!} \\

Hence the number of distinguishable permutations=\frac{11!}{1!2!4!4!}=34650 \\

4 0
3 years ago
What is the solution to<br> -10 = 5(2x – 4)
Taya2010 [7]
-10=5(2x-4)
-10=10x-20
+20 +20
10=10x
1=x
5 0
2 years ago
Read 2 more answers
Evaluate the surface integral. S x2z2 dS S is the part of the cone z2 = x2 + y2 that lies between the planes z = 4 and z = 5
sammy [17]
The surface S can be parameterized in cylindrical coordinates using

\mathbf r(u,v)=(x(u,v),y(u,v),z(u,v))=(u\cos v,u\sin v,u)

where 4\le u\le5 and 0\le v\le2\pi. The surface integral is then equivalent to

\displaystyle\iint_Sx^2z^2\,\mathrm dS=\int_{v=0}^{v=2\pi}\int_{u=4}^{u=5}(u\cos v)^2u^2\left\|\mathbf r_u\times\mathbf r_v\right\|\,\mathrm du\,\mathrm dv
=\displaystyle\sqrt2\int_{v=0}^{v=2\pi}\int_{u=4}^{u=5}u^5\cos^2v\,\mathrm du\,\mathrm dv
=\dfrac{3843\pi}{\sqrt2}
7 0
2 years ago
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