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kap26 [50]
3 years ago
11

Angela has 15 chocolate cookies. She eats 6 of them, then goes to the store and buys 1 more. How many cookies does Angela have n

ow?
Mathematics
1 answer:
mart [117]3 years ago
5 0

The answer is 10 cookies. All you have to do is subtract 6 from 15, and then add one to your previous answer. Finally, you have your answer!

Hope this helps! :D

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Please help.<br><br>Solve for x <br><br>​
Andreas93 [3]

Answer:

b i just dat.

Step-by-step explanation:

8 0
2 years ago
Find the mean absolute deviation for the set of data. Number of sibblings 2,5,8,9,7/6,3,5,1,4,
Tresset [83]

8,7,9,3,4,9,2

This is correct because I’m in middle school

7 0
3 years ago
Freddie is at chess practice waiting on his opponent's next move. He notices that the 4-inch-long minute hand is rotating around
Alex777 [14]
One complete revolution of the minute hand sweeps a central angle of 360° which is equivalent to 60 minutes.
That is, the minute hand creates
(360°/(60 min) = 6 degrees/min.

From 3:35 to 3:55 is 20 minutes.
It sweeps a central angle of
 (20 min)*(6 deg/min) = 120°

Because 360° = 2π radians,
120° = (120/360)*2π = (2π)/3 radians

Answer:
 \frac{2 \pi }{3} \,radians
In decimals, this is 2.1 radians (nearest tenth)

Part 2:
Because the minute hand is 4 inches long, the length of the arc swept is
(4 in)*(2π/3 radians) = 8π/3 inches

Answer:
 \frac{8 \pi }{3} \,inches
In decimals, this is 8.4 inches (nearest tenth).

  
7 0
3 years ago
Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).
Arisa [49]
The distance between a point (x,y,z) on the given plane and the point (0, 2, 4) is

\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}

but since \sqrt{f(x,y,z)} and f(x,y,z) share critical points, we can instead consider the problem of optimizing f(x,y,z) subject to x-2y+3z=6.

The Lagrangian is

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
L_y=2(y-2)-2\lambda=0\implies y=2+\lambda
L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2
L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6

Solve for \lambda:

x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6
\implies2=7\lambda\implies\lambda=\dfrac27

which gives the critical point

x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7

We can confirm that this is a minimum by checking the Hessian matrix of f(x,y,z):

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}
8 0
2 years ago
A rectangle has vertices P(-7, -5) , Q(-7, 8), R(3, 8), and S(3, -5). What is the length, in units, of RS¯¯¯¯¯¯¯? 3 units
cupoosta [38]
21 !; =47 she’d go gsmj. Fav
6 0
3 years ago
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