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adell [148]
3 years ago
12

chris has 5 1/2 cups of water in a pitcher. He pours 3/8 cup of water into a glass. How many cups of water is left in the pitche

r?
Mathematics
1 answer:
swat323 years ago
7 0

There's 5 1/8 cups of water left in the pitcher.

- 5 1/2 = 11/2


- 11/2 = 44/8


- 44/8 - 3/8 =41/8


- 41/8 = 5 1/8


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The product of -6 and a number is at least -72.
sesenic [268]
-6x>= -72. {x| 12>=x}

-72 (less than or equal to sign) -6x (product means multiply right?) all solutions is the value 12 and any value less
6 0
3 years ago
a car dealer buys a luxury car for $65,200 and sells it for 85,650. What is the percent increase in the price of the cara car de
nika2105 [10]

Answer:

The percent increase in the price of the car is <u>31.36%</u>.

Step-by-step explanation:

Given:

A car dealer buys a luxury car for $65,200 and sells it for $85,650.  

Now, to find the percent increase in the price of the car.

Cost price of the luxury car = $65,200.

Sell price of the luxury car = $85,650.

So, the price of the car increased by:

Sell price of the luxury car - Cost price of the luxury car.

=\$85,650-\$65,200\\\\=\$20,450.

<em>Thus, the price of car increased by $20,450.</em>

Now,to get the percent increase in the price of the car:

\frac{20450}{65200} \times 100

=0.3136\times 100

=31.36\%.

Therefore, the percent increase in the price of the car is 31.36%.

7 0
3 years ago
Can some help me with this please.
MrMuchimi
Zane was -25 meters from the edge of the volcano when he started:)
3 0
3 years ago
A store sells candy at $.50, $1, $1.50, $2, and $3 per kilogram. you can see that the unit price of candies that $3 buy very inv
olga nikolaevna [1]

Answer:

constant of variation = 3

Step-by-step explanation:

Given that a store is selling different candies costing  $.50, $1, $1.50, $2, and $3 per kilogram.

As given

Amount available to buy candies = $ 3

Suppose

Unit price of candies = x

Number of candies bough = y

Constant of variation = k

As we know the unit price of candies and number of candies bought vary inversely. As the unit price would increase the the number of candies bought in available amount ($3) would decrease.

So our formula to calculate formula for constant of variation would be as shown below:

k= xy →(1

Case 1

if we take unit price x to be $0.5, then we can buy 6 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (0.5)(6) = 3

Case 2

if we take unit price x to be $1, then we can buy 3 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1)(3) = 3

Case 3

if we take unit price x to be $1.5, then we can buy 2 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1.5)(2) = 3

Case 4

if we take unit price x to be $2, then we can buy 1.5 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (2)(1.5) = 3

Case 4

if we take unit price x to be $3, then we can buy 1 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (3)(1) = 3

So, our constant of variation is 3.

3 0
3 years ago
Can someone pls help me
Irina18 [472]

Answer:

6π Km

Step-by-step explanation:

The arc length is calculated as

arc = circumference of circle × fraction of circle

    = 2πr × \frac{120}{360}

   = 2π × 9 × \frac{1}{3}

   = 18π × \frac{1}{3}

  = 6π Km ← exact value

6 0
3 years ago
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