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3 years ago

After 9 months, the simple interest earned on an investment of $1200 is $72. find the interest rate.

1 answer:

7 0

Use the formula i=prt, where i is the interest earned, p is the principal, r is the rate (as a decimal fraction) and t is the elapsed time, in years.

Here i = $72 = $1200 r (9/12) (9 months is 9/12, or 3/4, of 1 year)
Reducing,
$72 = $900r
Solving for r, r=0.08, or 8 percent per year.

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7 divided by 2-4.5x3+8

lord [1]

Answer:

2-4.5×3+8=-3.8

-3.8÷7=-0.5

Step-by-step explanation:

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3 years ago

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Is this a polygon? If it is not a polygon please say why.

Eva8 [605]

Answer:

if you where trying to draw it straight then yes it is a polygon but if it is supposed to be rounded then no it is not.

Step-by-step explanation:

a plane figure with at least three straight sides and angles, and typically five or more.

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3 years ago

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Here is the graphed equation :)

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3 years ago

angelo rode his bike around a bike trail that was 1/4 of a mile long.he rode his bike around thetrail 8 times.Angelo says he rod

forsale [732]

Hi there!

From this problem we can pull out some key information and remove any excess.

- The trail is 1/4 of a mile long.
- Angelo rode around the trail 8 times.
- Angelo claims he rode 8/4 miles.
- Teresa claims he rode 2 miles.

From that we know that if Angelo rode around the trail 8 times and the trail is 1/4 a mile, he in total rode 8/4 of a mile.

However, Teresa claims he rode 2 miles!

And the answer is... they're both correct!

Angelo did indeed ride 8/4 miles however that is equivalent to 2 miles so they are both in the right.

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3 years ago

1. What is an equation for the line with slope 2/3 and y-intercept 9?

Monica [59]

Question 1:

The generic equation of the line is given by:
$y = mx + b
$
Where,
m: slope of the line
b: cutting point with the y axis
Substituting values we have:
$y = \frac{2}3}x + 9
$
Answer:
an equation for the line with slope 2/3 and y-intercept is:
$y = \frac{2}3}x + 9$

Question 2:

The standard equation of the line is given by:
$y-yo = m (x-xo)
$
Where,
m: slope of the line
(xo, yo): ordered pair that belongs to the line
The slope of the line is:
$m = \frac{y2-y1}{x2-x1}$
Substituting values:
$m = \frac{1-(-3)}{3-1}$
$m = \frac{1+3}{3-1}$
$m = \frac{4}{2}$
$m = 2
$
We choose an ordered pair:
$(xo, yo) = (3, 1)
$
Substituting values:
$y-1 = 2 (x-3)
$
Rewriting:
$y = 2x - 6 + 1

y = 2x - 5$
Answer:
An equation in slope-intercept form for the line that passes through the points (1, -3) and (3,1) is:
$y = 2x - 5
$

Question 3:

For this case, since the variation is direct, then we have an equation of the form:
$y = kx
$ Where,
k: constant of variation.
We then have the following equation:
$-4y = 8x
$ Rewriting we have:
$y = \frac{8}{-4}x
$
$y = -2x
$ Therefore, the constate of variation is given by:
$k = -2
$
Answer:
the constant of variation is:
$k = -2$

Question 4:

For this case, since the variation is direct, then we have an equation of the form:
$y = kx
$ Where,
k: constant of variation.
We must find the constant k, for this we use the following data:
y = 24 when x = 8
Substituting values:
$24 = k8
$ Clearing k we have:
$k = \frac{24}{8} 
$
$k = 3
$
Therefore, the equation is:
$y = 3x
$ Thus, substituting x = 10 we have that the value of y is given by:
$y = 3 (10)

y = 30$ Answer:
the value of y when x = 10 is:
$y = 30$

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3 years ago

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