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Zigmanuir [339]
3 years ago
9

An engineer is building a new water dam. She needs the turbine to spin at least 100,00 j of kinetic energy. If the reservoir hol

ds 1000g of water How fast must the water flow?
Physics
2 answers:
Kay [80]3 years ago
4 0

Answer:

The water must flow with the velocity of 141.4m/s

Explanation:

The kinetic energy is energy due to the motion of a body

In this Case the kinetic energy of the turbine is given as

KE=1/2mv²

Where KE= kinetic energy

m= mass of water

v= velocity of the water

Data given

KE=10000j

m=1000g------kg =1000/1000= 1kg

v=?

Substituting our data into the expression we have

10,000=1/2(1*v²)

10,000=v²/2

Solving for v we have

v²=20,000

v=√20,000

v=141.4m/s

TiliK225 [7]3 years ago
3 0

Answer:

v = 141.42 m/s

Explanation:

Mass of the water, M = 1000g = 1 kg

Kinetic energy of the turbine, KE = 10000 J

The speed of the water, v = ?

KE = 0.5 Mv²

10000 = 0.5 * 1 * v²

v² = 10000/0.5

v² = 20000

v = √20000

v = 141.42 m/s

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A physics demo launches a ball horizontally while dropping a second ball vertically at exactly the same time. 1) which ball hits
Simora [160]

Answer:

Both balls will hit the ground at the same time

Explanation:

The factor which leads to ball falling is the gravity acting on the ball;

The motions along the path of both balls are independent and both balls will obey the following illustration

Using the third equation of motion

s = ut + ½at²

Where s = distance covered by both balls.

u = initial velocity of both balls. Since both balls start from rest, u = 0m/s

a = acceleration; and it's equal to acceleration due to gravity.

a = g

By substituton

s = 0 * t + ½gt²

s = 0 + ½gt²

s = ½gt²

Make t the subject of formula

gt² = 2s

t² = 2s/g

t = ±√(2s/g)

But time can't be less than 0 (in other words, negative)

So,

t = √(2s/g)

It'll take both balls √(2s/g) time to hit the floor

6 0
3 years ago
Read 2 more answers
Your laundry basket Please 22 is in your room is 3.0 M above you on the second floor it takes you 6.0 seconds to carry the laund
Rainbow [258]

Power = (work done) / (time to do the work)

Work done = (force to lift the object) x (distance lifted)

In this question, the force is the (weight of the basket)+(your weight).

Work done = (weight of basket+you) x (3 meters)

Time to do the work = 6 seconds.

Power = (weights x 3 meters) / (6 seconds)

<em>Power = (1/2)·(weight of the basket+you, in Newtons) watts</em>

8 0
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A toy rocket is launched vertically from ground level (y = 0.00 m), at time t = 0.00 s. The rocket engine provides constant upwa
Ksju [112]

The toy rocket is launched vertically from ground level, at time t = 0.00 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 72 m and acquired a velocity of 30 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground with negligible air resistance.

The total energy of the rocket, which is a sum of its kinetic energy and potential energy, is constant.

At a height of 72 m with the rocket moving at 30 m/s, the total energy is m*9.8*72 + (1/2)*m*30^2 where m is the mass of the rocket.

At ground level, the total energy is 0*m*9.8 + (1/2)*m*v^2.

Equating the two gives: m*9.8*72 + (1/2)*m*30^2 = 0*m*9.8 + (1/2)*m*v^2

=> 9.8*72 + (1/2)*30^2 = (1/2)*v^2

=> v^2 = 11556/5

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3 0
3 years ago
19. A small dog is trained to jump straight up a distance of 1.2 m. How much kinetic energy does the 7.2-kg dog need to jump thi
vova2212 [387]
<span>How much kinetic energy does a 7.2-kg dog need to make a vertical jump of 1.2 m?
</span>Answer:

85 Joule (approx)

Explanation:

Potential energy at highest point

<span><span>P.E = mgh = 7.2 kg × 9.8 m/s2</span>×1.2 m≈85 Joule</span>

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