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slava [35]
3 years ago
11

Based on how stars are named, which star is probably brightest

Physics
2 answers:
vazorg [7]3 years ago
5 0

The name of the brightest star is ursae majoris. it is a dwarf star and lie in the constellation of ursa major. that is why it has such similar name. around this star , we have three planets around this star. the distance of this star is around 46 light years. also it's mass is almost same as that of the sun. it rotates with a period of 24 hours

kvv77 [185]3 years ago
4 0
Sirius<span> is the brightest star known to earth . </span>
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Do you think radio waves and x-rays are types of light?
goblinko [34]

Answer:

yes, radio waves and x-rays are type of light.

6 0
3 years ago
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An amusement park designer wants his swing to have a centripetal acceleration of 24 m/s2. If the velocity of the swing is 11 m/s
viva [34]

Answer:

<u>radius</u><u> </u><u>is</u><u> </u><u>C</u><u>:</u><u> </u><u>5</u><u>.</u><u>0</u><u> </u><u>m</u>

Explanation:

formular for centripetal acceleration:

a =  \frac{ {V}^{2} }{r}

a is acceleration

V is velocity

r is radius

24 =  \frac{ {11}^{2} }{r}  \\  \\ r =  \frac{ {11}^{2} }{24}  \\  \\ r = 5.0 \: m

5 0
3 years ago
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A cart of mass 20 kg, initially at rest, is pushed with a net force of 40 N on a flat surface. If the cart is pushed 5 m, what i
bixtya [17]
Using the theorem of kinetic energy
1/2mVf² - 1/2mVi²= WF + Wp,     Wp=0
WF = F. AB, AB=5m and F= 40N, m=20kg
so the final kinetic  is KEf= 1/2mVf² = WF =<span>F. AB= 40*5=200J
</span>
the final velocity is 1/2mVf² <span>=200, implies   Vf= sqrt(20)=2sqrt(5)m/s</span>

3 0
3 years ago
Once again we have a skier on an inclined plane. The skier has mass M and starts from rest. Her speed at the bottom of the slope
mars1129 [50]

Answer:

v = 31.3 m / s

Explanation:

The law of the conservation of stable energy that if there are no frictional forces mechanical energy is conserved throughout the point.

Let's look for mechanical energy at two points, the highest where the body is at rest and the lowest where at the bottom of the plane

Highest point

       Em₀ = U = m g y

Lowest point

     Em_{f} = K = ½ m v²

As there is no friction, mechanical energy is conserved

       Em₀ = Em_{f}

       m g y = ½ m v²

       v = √ 2 g y

Where we can use trigonometry to find and

       sin 30 = y / L

       y = L sin 30

Let's replace

      v = RA (2 g L sin 30)

Let's calculate

      v = RA (2 9.8 100.0 sin30)

      v = 31.3 m / s

4 0
3 years ago
What is the total distance that the object traveled?
Natasha_Volkova [10]

Answer:

for what?

Explanation:

d=S x T

or

d=vt+1/2at2

srry if wrong but

hope this helps

take care

8 0
3 years ago
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