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slava [35]
3 years ago
11

Based on how stars are named, which star is probably brightest

Physics
2 answers:
vazorg [7]3 years ago
5 0

The name of the brightest star is ursae majoris. it is a dwarf star and lie in the constellation of ursa major. that is why it has such similar name. around this star , we have three planets around this star. the distance of this star is around 46 light years. also it's mass is almost same as that of the sun. it rotates with a period of 24 hours

kvv77 [185]3 years ago
4 0
Sirius<span> is the brightest star known to earth . </span>
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Científico que formuló 3 leyes de astronomía
s2008m [1.1K]

Answer:

El astrónomo alemán Johannes Kepler

Explanation:

Primera Ley:

Los planetas giran alrededor del Sol siguiendo una trayectoria elíptica. El Sol se sitúa en uno de los focos de la elipse.

La excentricidad e de una elipse es una medida de lo alejado que se encuentran los focos del centro.

Pues bien, la mayoría de las órbitas planetarias tienen un valor muy pequeño de excentricidad, es decir e ≈ 0. Esto significa que, a nivel práctico, pueden considerarse círculos descentrados.

Segunda Ley:

La recta que une el planeta con el Sol barre áreas iguales en tiempos iguales.Para que esto se cumpla, la velocidad del planeta debe aumentar a medida que se acerque al Sol. Esto sugiere la presencia de una fuerza que permite al Sol atraer los planetas, tal y como descubrió Newton años más tarde.

Tercera ley de Kepler:

La tercera ley, también conocida como armónica o de los periodos, relaciona los periodos de los planetas, es decir, lo que tardan en completar una vuelta alrededor del Sol, con sus radios medios.

Para un planeta dado, el cuadrado de su periodo orbital es proporcional al cubo de su distancia media al Sol.

4 0
3 years ago
What is the acceleration of a car initially traveling at -5m/s and<br> reaching -22m/s in 3s.
lozanna [386]

Answer:

a=-5.67\ m/s^2

Explanation:

Given that,

Initial velocity, u = -5 m/s

Final velocity, v = -22 m/s

Time, t = 3s

We need to find the acceleration of the car. The formula of it is given by :

Acceleration,

a=\dfrac{v-u}{t}\\\\a=\dfrac{(-22)-(-5)}{3}\\\\a=-5.67\ m/s^2

So, the acceleration of the car is -5.67\ m/s^2.

4 0
3 years ago
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