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slava [35]
3 years ago
11

Based on how stars are named, which star is probably brightest

Physics
2 answers:
vazorg [7]3 years ago
5 0

The name of the brightest star is ursae majoris. it is a dwarf star and lie in the constellation of ursa major. that is why it has such similar name. around this star , we have three planets around this star. the distance of this star is around 46 light years. also it's mass is almost same as that of the sun. it rotates with a period of 24 hours

kvv77 [185]3 years ago
4 0
Sirius<span> is the brightest star known to earth . </span>
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A person of mass 55 kg swings on a rope length 4 m from rest (when the rope makes an angle of 30 degrees with the vertical) and
vovangra [49]

Answer:

θ = 19.66°

Explanation:

To determine the angle that the rope makes with the vertical for the two people, you first take into account the potential energy of the first person before he swings on the rope:

U=mgh

h: distance to the ground

g: gravitational acceleration = 9.8m/s^2

m: mass of the first person = 55 kg

In the image attache below you can notice that the height h is:

h=4-4cos(30\°)=0.53m

Then, the potential energy is:

U=(55kg)(9.8m/s^2)(0.53m)=285.67J

When the first person picks up the second person (when the rope is exactly vertical), all the potential energy becomes kinetic energy. Next, when both people reaches the maximum height h' the energy must be equal to the initial potential energy of the first person:

U'=(m_1+m_2)gh'=285.67\ J

From the previous equation you can get h':

h'=\frac{285.67J}{(55kg+70kg)(9.8m/s^2)}=0.2332m

Finally, you obtain the angle between the rope at the height h,' and the vertical, by calculating the following:

h'=4-4cos(\theta)\\\\\theta=cos^{-1}(\frac{4-h'}{4})=cos^{-1}(\frac{4-0.2332}{4})=19.66\°

hence, the angle between the rope and the vertical, when the two people are in the rope is 19.66°

8 0
3 years ago
What is the mass of a crate if a force of 200 N causes t to accelerate at 8 ms? (Formula F=ma)
oee [108]
Hey there! :D

Plug in what you know. 

F=ma

F= force m= mass a= acceleration 

200 N= m*8 ms

Divide both sides by 8. 

m= 25

The mass is 25. 

I hope this helps!
~kaikers 
6 0
4 years ago
Read 2 more answers
Objects 1 and 2 attract each other with a gravitational force
snow_tiger [21]

Answer:

F' = 162 units

Explanation:

The gravitational force of attraction between the two objects is given by Newton's Gravitational law through the following formula:

F = \frac{Gm_{1}m_{2}}{r^{2}}\\\\

where,

F = gravitational force = 18 units

G = Gravitational Constant

m₁ = mass of object 1

m₂ = mass of object 2

r = distance between objects

Therefore,

18 = \frac{Gm_{1}m_{2}}{r^{2}}------ eqn (1)\\\\

Now, if we change the value of distance to one-third of original value, then:

r' = r/3

F' = \frac{Gm_{1}m_{2}}{(\frac{r}{3})^{2}}\\\\F' = (9)(\frac{Gm_{1}m_{2}}{r^{2}})

using eqn (1):

F' = 9(18 units)

<u>F' = 162 units</u>

7 0
3 years ago
Nick, a 60 kg physics student, wants to go bungee jumping, but doesn't have a bungee cord. He finds a 15 m long, strong spring (
vitfil [10]

Answer:

h = 24.81 m

Explanation:

Given:-

- The mass of the student, m = 60 kg

- The length of the spring, L = 15 m

- The spring constant, k = 60 N/m

Find:-

How far below the bridge is he hanging

Solution:-

- First realize that after the student attempts a bungee jump he oscillates violently ( dynamic motion ). After some time all the kinetic energy has been converted to Elastic and gravitational potential energy student is (stationary) and hanging down on one end of the spring.

- We will apply equilibrium condition on the student. We see that there are two forces acting on the student. The weight (W) of the student acting downward is in combat with the spring restoring force (Fs) acting upwards.

- Apply equilibrium condition in vertical direction:

                               Fs - W = 0

                               Fs = W

- The weight and spring force can be expressed as:

                               k*x = m*g

Where,     g : Gravitational acceleration constant = 9.81 m/s^2

                x : The extension of the spring from original position

- Solve for the extension (x) of the spring for this condition.

                              x = m*g / k

- Plug in the values and evaluate:

                              x = (60 kg)*(9.81 m/s^2) / (60 N/m)

                              x = 9.81 m

- The spring extends for about 9.81 m from its original length. So the distance (h) from edge of the bridge would be:

                              h = L + x

                              h = 15 + 9.81

                              h = 24.81 m

4 0
3 years ago
This chart shows characteristics of three different waves, all with the same wavelength of 10 m but moving at different Which st
JulijaS [17]

Answer:

Wave X is moving the fastest.

Explanation:

As we know that the speed of the wave is given as the product of frequency and wavelength

so here we will have

\lambda = 10 m

now for wave X

f = 6 Hz

now the speed of this wave is

v_x = 10 \times 6 = 60 m/s

now for wave Y

f = 0.5 Hz

now the speed of this wave is

v_y = 10 \times 0.5 = 5 m/s

now for wave Z

f = 2 Hz

now the speed of this wave is

v_z = 10 \times 2 = 20 m/s

So correct answer will be

Wave X is moving the fastest.

3 0
3 years ago
Read 2 more answers
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