The amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is is 8 times the initial amount of heat.
<h3>What is heat?</h3>
The temperature increment will lead to the increase in the internal energy of the object. This internal energy is the heat.
Given is the change in temperature ΔT = 7-4 =3°C., diameter D to 2D,
Q = Cp x ρ(4π/3)D³ x 3..................(1)
and Q' = Cp x ρ(4π/3)(2D)³ x 3
Q' = Cp x ρ(4π/3)8D³x 3..................(2)
Dividing both the equation, we have
Q' / Q =8
Q' = 8Q
Thus, the amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is 8 times the initial amount of heat.
Learn more about heat.
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Adding thermal energy
Performing work on the system
This is a Doppler effect. Generally, if you move to a frequency source, you would detect an increase in frequency and when you move away from a source you would detect a decrease.
For this question, before you pass them, you are actually approaching them, so you would hear a higher frequency than the constant 300 Hz they are playing at.
Using the condensed formula:
f ' = ((v <u>+</u> vd)/(v <u>+</u> vs)) * f
Where: vd = Velocity of the detector.
vs = Velocity of the frequency source.
v = Velocity of sound in air.
f ' = Apparent frequency.
f = Frequency of source.
v = 343 m/s, vd = detector = 27.8 m/s, vs = velocity of the source =0. (the flautists are not moving).
f = 300 Hz.
There would be an overall increase in frequency, so we maintain a plus at the numerator and a minus at the denominator.
f ' = ((v + vd)/(v - vs)) * f
f ' = ((343+ 27.8)/(343 - 0)) * 300
= (370.8/343)* 300 = 324.3
Therefore frequency before passing them = 324.3 Hz.
Cheers.
Answer: two way gravity is affected if somethings weight is doubled or grtavity gets weaker with distance
Explanation:
