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2 years ago

A complex fraction is a fraction of a fraction. True False

2 answers:

5 0

True because a complex fraction is a fraction where either the numerator, denominator, or both have a fraction in them.

dsp732 years ago

3 0

Answer:

The answer is TRUE

Step-by-step explanation:

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Of the CP of 15 articles equals to the SP of 12 articles, find the gain percent. an ple 4:

Rasek [7]

Question

If the CP of 15 articles equals to the SP of 12 articles, find the gain percent.

Answer:

gain percent = 25%

Step-by-step explanation:

To solve the question given, we will follow the steps below:

gain% = $\frac{s.p - c.p}{c.p}$ × 100%

But from the question;

"CP of 15 articles equals to the SP of 12 articles", this implies that

15 c.p = 12 s.p

s.p = 15c.p / 12

s.p = $\frac{15 c.p}{12}$ = $\frac{5c.p}{4}$

s.p = $\frac{5c.p}{4}$

substitute s.p = $\frac{5c.p}{4}$ into the formula

gain% = $\frac{s.p - c.p}{c.p}$ × 100%

= $\frac{\frac{5c.p}{4} - c.p }{c.p}$ × 100%

= $\frac{\frac{5c.p - 4c.p}{4} }{c.p}$ × 100%

= $\frac{c.p}{4}$ ÷ c.p × 100%

= $\frac{c.p}{4}$ × $\frac{1}{c.p}$ × 100%

= $\frac{1}{4}$ × 100%

= 25 %

3 0

3 years ago

Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student

AysviL [449]

Answer:

The mean calculated for this case is $\bar X=584$

And the 95% confidence interval is given by:

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=584$

The sample deviation calculated $s=86.776$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that $t_{\alpha/2}=2.776$

Now we have everything in order to replace into formula (1):

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

3 0

2 years ago

What is the value of x when h(x)=-3? -7

Pachacha [2.7K]

Answer:

○ -1

Step-by-step explanation:

Looking closely at this piecewise function, when the line on the left-hand side intersects at -3 = y, x is -1.

I hope this helps, and as always, I am joyous to assist anyone at any time.

7 0

2 years ago

Find three consecutive odd integers so that the sum of twice the first, the second

netineya [11]

Answer: 23, 25, 27

Step-by-step explanation:

Let the 3 consecutive odd numbers be x, x+2 and x+4.

2x+(x+2)+3(x+4)=152

2x + x + 2 + 3x + 12 = 152

6x+14=152

6x = 152 - 14

x=138/6

x=23

So, the numbers are 23, 25 and 27.

7 0

3 years ago

What is the equation for the line that goes through points (3,6) and (-3,-2)?

Basile [38]

Unless unusually unusual unification under

5 0

2 years ago