<h3>
<em><u>1</u></em><em><u>3</u></em><em><u>5</u></em><em><u>.</u></em></h3>
Step-by-step explanation:
<em>3</em><em>³</em><em>.</em><em> </em><em>(</em><em>1</em><em>2</em><em> </em><em>-</em><em> </em><em>2</em><em>÷</em><em>)</em>
<em>↓</em>
<em>Calculate</em><em> </em><em>the </em><em>sum </em><em>of </em><em>difference</em>
<em>↓</em>
<em>3</em><em>³</em><em> </em><em>×</em><em> </em><em>1</em><em>0</em><em> </em><em>÷</em><em> </em><em>2</em>
<em>↓</em><em> </em>
<em>Calculate</em><em> the</em><em> </em><em>power</em>
<em>↓</em>
<em>2</em><em>7</em><em> </em><em>×</em><em> </em><em>1</em><em>0</em><em> </em><em>÷</em><em> </em><em>2</em>
<em>CHECK✓</em><em> </em><u>135</u><u>.</u>
<u>(</u><u>Confirmation</u><u> </u><u>Answer:</u><u>1</u><u>3</u><u>5</u><u> </u><u>✓</u><u> </u><u>)</u>
<u>Alternative</u><u> </u><u>Forms </u><u>:</u>
<u>1</u><u>.</u><u>3</u><u>5</u><u> </u><u>×</u><u> </u><u>1</u><u>0</u><u>²</u>
<em>Hoping </em><em>this </em><em>helps </em><em>u,</em><em> </em><em>Have </em><em>a </em><em>great </em><em>day!</em><em>:</em><em>)</em>
<em><u>#Bra</u></em><em><u>i</u></em><em><u>nlyeveryday>^_^<</u></em>

To get the domain of a function, the function must output a number that is not a division by zero or a square root of a negative number.
Also the graphs seemed to be like
.
If we let your graph be y
This equation must be the graph.
If a function shouldn't output a square root of a negative number so it must be
so that there will be no negative number under the radical sign.

Also we can see that the graph has no y's for x's lesser than -2
When you put the pieces of the field together, you have a rectangle that's 53 yards
wide and 120 yards long.
When you draw the diagonal, it divides the field into two right triangles.Each one
has legs with lengths of 120 yards and 53 yards. The diagonal of the field is the
hypotenuse of both right triangles.
(120)² + (53)² = (the hypotenuse)²
14,400 + 2,809 = (the hypotenuse)²
17,209 = (the hypotenuse)²
The diagonal (hypotenuse) = √17,209 = 131.183... yards (rounded)
I guess that's the longest straight line it is possible to run on a football field
while staying in bounds.
Answer: 3 4/9 and 4 19/29
Step-by-step explanation: Mixed fractions can be converted into improper fractions. Example: 3 1/2=
3×2+1= 7/2
So, 3 4/9= 3×9+4= 31/9
4 19/29= 4×29+19= 135/29
PLEASE RATE 5 STARS AND VOTE AS BRAINLIEST:)
(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)