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3 years ago

Sixty three and five hundredths in numeral form

Mathematics

1 answer:

Sidana [21]3 years ago

6 0

63.05

the and is like the dot

it goes, tenths, hundtedths, and thousandths

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Yolanda spends 8/23 hours per month playing soccer. Approximately how many hours does she play soccer in a year

Novosadov [1.4K]

Given:
8 2/3 hours per month
12 months in a year.

Number of hours she play soccer in a year.

8 2/3 must be converted to improper fraction.

((8*3)+2)/3 = 26/3

26/3 * 12 = (26 * 12)/3 = 312/3 = 104

Yolanda spends 104 hours in a year playing soccer.

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3 years ago

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storchak [24]

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3 years ago

5. Ms. Sellers flew out to Utah to take her sons to college. If she flew 245.6

lara31 [8.8K]

Answer:

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distance flown in 5.4 hours = 245.6 miles

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3 years ago

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Y=sqrt(x)(8x-5) find the derivative

garri49 [273]

Answer:

$\displaystyle y' = \frac{24x - 5}{2\sqrt{x}}$

General Formulas and Concepts:

Algebra I

Exponentials [Fractions] - Are radicals
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \sqrt{x}(8x - 5)$

Step 2: Differentiate

$\displaystyle f(x) = \sqrt{x}, \ g(x) = (8x - 5)$

Product Rule: $\displaystyle y' = \frac{d}{dx}[\sqrt{x}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]$
Rewrite: $\displaystyle y' = \frac{d}{dx}[x^{\frac{1}{2}}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]$
Basic Power Rule: $\displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{1 - 1}$
Simplify: $\displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{0}$
Rewrite: $\displaystyle y' = \frac{1}{2x^{\frac{1}{2}}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8$
Multiply: $\displaystyle y' = \frac{8x + 5}{2x^{\frac{1}{2}}} + 8\sqrt{x}$
Rewrite: $\displaystyle y' = \frac{8x + 5}{2\sqrt{x}} + 8\sqrt{x}$
Add/Rewrite: $\displaystyle y' = \frac{24x - 5}{2\sqrt{x}}$

3 0

3 years ago

How to change decimal to a fraction

Ksju [112]

Put the number that the decimal is over the place that it is in
example
.5
every space after the decimal is multiplied by 10
tenths place 0.1
hundreths 0.01
thousanths 0.001
etc
so .5 is in the tenths place so the fraction would be 5/10
the decimal is now converted into a fraction

another example
.07 is in the hundreths so it would be 7/100

final example
.25 is in the hundredths place since the last number lands on the hundreths column
it would be 25/100

if possible you can simplify if that is what is needed

3 0

4 years ago