5 • ((3x^2 • y)^3)<span>
(5•3^3x^6y^3) would be the answer
hope this helps
</span><span>
</span>
Answer:
Area of second circle = 56cm² +
Area of second circle = 2179.71cm²
Step-by-step explanation:
let the radius of the small circle be r and that of the big circle be R
Area small circle =
Area Big circle =
Area Big circle - Area small circle = 56cm²
- =56cm²
The second circle is the bigger circle.
Area of second circle - =56cm²
Area of second circle = 56cm² +
r =26cm
Area of second circle = 56cm² +
Area of second circle = 56cm² +
Area of second circle = 56cm² +
Area of second circle = 56cm² + 2123.71
Area of second circle = 2179.71cm²
Answer:
50*
Step-by-step explanation:
Answer:
TU ≅ CB
Step-by-step explanation:
HL Postulates that when a leg and the hypotenuse of a right triangle are congruent to a corresponding leg and hypotenuse of another, then both right triangles are congruent.
Both right triangles shown in the diagram above is indicated to possess corresponding lengths of a leg, that is side UV ≅ side BA
We need an additional information that shows that the hypotenuse, TU, of ∆TUV is congruent to the hypotenuse, CB of ∆CBA.
Therefore, additional information needed is TU ≅ CB