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harina [27]
3 years ago
10

Please someone help

Mathematics
1 answer:
Volgvan3 years ago
4 0
Its -1,3 

<span>y=4<span>x2</span>+8x+7</span>

There is a formula for finding the vertex=       <span>y=a<span>x2</span>+bx+c</span>

<span>h=−<span>b<span>2a</span></span></span> and <span>k=c−<span><span>b2</span><span>4a</span></span></span>

Solve for h with <span>a=4</span> and <span>b=8</span> and <span>c=7</span>

<span>h=−<span>b<span>2a</span></span>=<span><span>−8</span><span>2⋅4</span></span>=−1</span>

<span><span>
=</span>−<span>b<span>2a</span></span>=<span><span>−8</span><span>2⋅4</span></span>=−1</span>

Solve for k

<span>k=c−<span><span>b2</span><span>4a</span></span>=7−<span><span>82</span><span>4⋅4</span></span>=7−<span>6416</span>=7−4=3</span>

Our vertex is at <span>(−1,3)</span>

 <span>y=4<span>x2</span>+8x+7</span> with vertex at <span>(−1,3)</span> 

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The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).

<h3>How to analyze quadratic equations</h3>

In this question we have a graph of a <em>quadratic</em> equation translated to another place of a <em>Cartesian</em> plane, whose form coincides with the <em>vertex</em> form of the equation of the parabola, whose form is:

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By direct comparison we notice that (h, k) = (5, 1) and C = 1. Now we proceed to check if the points (x, y) = (2, 10) and (x, y) = (8, 10) belong to the parabola.

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