Factors are what is being multiplied or divided. In this problem, you have 6 times X times Y. So, you have 3 factors.
First, you need to substitute the value of x in all of the x spots.
2x+3
2(3)+3. Us PEMDAS to solve the problem.
6+3
9
I think that there’s around 16 squares.
Answer:
See below ~
Step-by-step explanation:
Given :
<u>QRSTU ~ FGCDE</u>
Finding the scale factor :
- Take two corresponding sides in proportion
- RS : GC
- 40 : 12
- <u>10 : 3</u>
Applying the scale factor to find the missing sides :
- FG :
- QR : FG = 10 : 3
- 30/FG = 10/3
- FG = 30/10 x 3
- FG = 3 x 3
- <u>FG = 9</u>
- CD :
- ST : CD = 10 : 3
- 40/CD = 10/3
- CD = 40/10 x 3
- CD = 4 x 3
- <u>CD = 12</u>
- EF :
- UQ : EF = 10 : 3
- 30/EF = 10/3
- EF = 30/10 x 3
- EF = 3 x 3
- <u>EF = 9</u>
<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
