Let

. Then

, and so as

, you have

. The limit is then equivalent to
Answer:
17 tenths - 8 tenths=9 tenths
Step-by-step explanation:
1.7 tenths is 17 tenths, we can see that by multiplying 1.7x10 to get 17
dot he sam with 0.8 to get 8 tenths
ti find the answer, subtract the units. 17-8=9
Answer: 
Step-by-step explanation:
Given

lies in the fourth quadrant
So, sine must be negative in the fourth quadrant
Using identity
to find sine value


Answer:
1. A. AC=3IN
2. D AND C
Step-by-step explanation:
(X)(3.25)(4)= 110.5
4
(x)(3.25)= 27.625
3.25
x = 8.5
(8.5)(3.25)(4)= 110.5