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gladu [14]
4 years ago
12

Write an absolute value equation to satisfy the given solution set shown on a number line.

Mathematics
1 answer:
aivan3 [116]4 years ago
8 0

Answer: IX - 4I ≤ 4

Step-by-step explanation:

In the numer line we can see that our possible values of x are in the range:

0 ≤ x ≤ 8

And we want to find an absolute value equation such that this set is the set of possible solutions.

An example can be:

IX - 4I ≤ 4

To construct this, we first find the midpoint M of our set, in this case is 4.

Then we write:

Ix - MI  ≤ IMI

Notice that i am using the minor and equal sign, this is because the black dots means that the values x = 0 and x = 8 are included, if the dots were empty dots, it would be an open set and we should use the <  > signs.

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sergij07 [2.7K]

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Step-by-step explanation:

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Exponential growth/decay problem 2
lapo4ka [179]

Answer:

a) decay

b) 2,950,000

c) 0.025

d) f(x)=2950000(0.975)^x

e) 2,409,123

Step-by-step explanation:

<u>Part (a)</u>

Exponential DECAY, since the population was decreasing annually.

<u>Part (b)</u>

Initial amount = 2,950,000 people (in the year 2000)

<u>Part (c)</u>

Decay factor = 2.5% = 0.025 (in decimal form)

<u>Part (d)</u>

General form of exponential decay function:

f(x)=a(1-r)^x

where:

  • a = initial amount
  • r = rate of decay (in decimal form)
  • x = time (in years)

Given:

  • a = 2950000
  • r = 0.025

\implies f(x)=2950000(1-0.025)^x

\implies f(x)=2950000(0.975)^x

<u>Part (e)</u>

To determine the city's population in 2008:

x = 2008 - 2000 = 8

\begin{aligned}\implies f(8) & =2950000(0.975)^8\\ & = 2409123\: \sf(nearest\:whole\:number)\end{aligned}

7 0
2 years ago
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