Question

Consider the following system of equations:

Answer 1

Answer:

Line$y=-2x+3$ intersects line $y=x-5$

Step-by-step explanation:

We are given that

$y=-2x+3$

$y=x-5$

Subtract one equation from other then we get

$-3x+8=0$

$3x=8$

$x=\frac{8}{3}$

Substitute the value of x in first equation then we get

$y=-2(\frac{8}{3})+3=-\frac{16}{3}+3=-\frac{-7}{3}$

Hence, the solution $(\frac{8}{3},-\frac{7}{3})$ is the intersection point of two line  equations .

Answer:Line$y=-2x+3$ intersects line $y=x-5$