I know the answer; just giving out points. 4a^3*b^2*3a∧-4*b^-3 Simplify as much as you can.
1 answer:
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<u><em>Answer:</em></u>
1. Couples tickets: $8
Individual tickets: $4
2. Song download cost: $2
Movie download cost: $15
<u><em>Step-by-step explanation:</em></u>
You can solve both of these questions by doing system of equations.
Let's start with question 1.
There are 2 variables in this equation:
- Couples tickets price: let's represent these with the letter C
- Individual tickets price: let's represent these with the letter K
Writing the two equations would look this these:
5c + 2k = 48
3c + 2k = 32
Next, isolate a variable. I am going to isolate K in the first equation.
Now that we isolated a variable we can plug that back in to the second equation:
We found that c is equal to 8 so we can put that back in to an equation to solve for k.
5(8) + 2k = 48
40 + 2k = 48
2k = 8
k = 4
Therefore, the price for couples tickets is $8 and the price for individual tickets is $4.
<u><em>Check #1:</em></u>
5(8) + 2(4) = 48
40 + 8 = 48
48 = 48
3(8) + 2(4) = 32
24 + 8 = 32
32 + 32
Now, let's go on to question 2.
There are 2 variables in this equation:
- Price of songs downloaded: let's represent these with S
- Price of movies downloaded: let's represent these with M
Writing the two equations would look like this:
15s + 11m = 195
15s + 8m = 150
There is a simple way to answer this system, however.
If you change the bottom equations signs to negative you can minus the second equation from the first equation like this:
15s + 11m = 195
-(15s +8m = 150)
Minus them to get this equation:
3m = 45
Solve
m = 15
We have found that each movie download costs $15, now let's plug this back into an equation:
15s + 11(15) = 195
15s + 165 = 195
15s = 30
s = 2
Each song costs $2 to download.
<em><u>Check #2:</u></em>
15(2) + 11(15) = 195
30 + 165 = 195
195 = 195
15(2) + 8(15) = 150
30 + 120 = 150
150 = 150
<em>I hope this helps!!</em>
<em>- Kay :)</em>
PEMDAS
P - Parentheses (or other grouping symbols)
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction
![8x[(7+4)x^2] - [(11-7)x^4]\\ \\ 8x[(11)x^2] - [(4)x^4] \\ \\ 8x[11x^2] - [4x^4] \\ \\ 88x^3 - 4x^4 \\ \\ -4x^4+88x^3](https://tex.z-dn.net/?f=8x%5B%287%2B4%29x%5E2%5D%20-%20%5B%2811-7%29x%5E4%5D%5C%5C%20%20%5C%5C%208x%5B%2811%29x%5E2%5D%20-%20%5B%284%29x%5E4%5D%20%5C%5C%20%20%5C%5C%208x%5B11x%5E2%5D%20-%20%5B4x%5E4%5D%20%5C%5C%20%20%5C%5C%2088x%5E3%20-%204x%5E4%20%5C%5C%20%20%5C%5C%20-4x%5E4%2B88x%5E3%20)
If you then want to go on to factor it, your answer would be
P - Parentheses (or other grouping symbols)
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction
If you then want to go on to factor it, your answer would be