Answer:
48.84mL
Explanation:
H2SO4 + 2KOH → K2SO4 + 2H2O
From the question:
nA = 1
nB = 2
From the question given we obtained the following information:
Ma = 0.43M
Va =?
Mb = 0.35M
Vb = 120mL
Using MaVa / MbVb = nA/nB, we can easily find the volume of the acid required. This is illustrated below:
MaVa / MbVb = nA/nB
0.43 x Va / 0.35 x 120 = 1/2
Cross multiply to express in linear form
2 x 0.43 x Va = 0.35 x 120
Divide both side by the (2 x 0.43)
Va = (0.35 x 120) /(2 x 0.43)
Va = 48.84mL
Therefore, the volume of H2SO4 required is 48.84mL
Ideal gas law, Charles law, Boyle's law.
<u>Explanation:</u>
Gas laws:
Charles law: Volume of a gas is directly proportional to the temperature.
V∝T
Boyle's law : Pressure of a gas is inversely proportional to the volume of a gas at constant temperature.
PV= k
Ideal gas law is the combined law of Charles and Boyle's law, PV = nRT.
We have to know the solubility of CaF₂.
The solubility of CaF₂ is: (c) 2.1 x 10-4 Molar
The general expression of solubility product of any sparingly soluble salt (having solubility S) with formula 
is: 
.
For the compound, CaF₂, x=1, y=2 So, 
=
=4S³= 3.9 x 10-11 (Given)
S³=
S³=9.75 X 
S= 2.1 X 
Molar
Answer:
<u>The deviations are :</u>
- <u>The activation energy which changes with temperature</u>
- <u>The arrhenius constant which depends on the temperature</u>
Explanation:
- There are deviations from the Arrhenius law during the glass transition in all classes of glass-forming matter.
- The Arrhenius law predicts that the motion of the structural units (atoms, molecules, ions, etc.) should slow down at a slower rate through the glass transition than is experimentally observed.
- In other words, the structural units slow down at a faster rate than is predicted by the Arrhenius law.
- <em>This observation is made reasonable assuming that the units must overcome an energy barrier by means of a thermal activation energy. </em>
- The thermal energy must be high enough to allow for translational motion of the units <em>which leads to viscous flow of the material.</em>
- Both the Arrhenius activation energy and the rate constant k are experimentally determined, and represent macroscopic reaction-specific parameters <em>that are not simply related to threshold energies and the success of individual collisions at the molecular level. </em>
- Consider a particular collision (an elementary reaction) between molecules A and B. The collision angle, the relative translational energy, the internal (particularly vibrational) energy will all determine the chance that the collision will produce a product molecule AB.
- Macroscopic measurements of E(activation energy) and k(rate constant ) <em>are the result of many individual collisions with differing collision parameters. </em><em>They are averaged out to a macroscopic quantity.</em>
