An alkane with the formula C6H14 can be prepared by hydrogenation of either of two precursor alkenes having the formula C6H12.

Chemistry

2 answers:

PIT_PIT [208]3 years ago

7 0

Answer:

2-methylpentane

Explanation:

Hello,

On the attached document, you will find the solution for this exercise. It is important for you to notice that at the reactions there are two possible precursors, 2-methylpentene and 4-methylpentene which are suitable to form 2-methylpentane via hydrogenation.

Best regards.

ankoles [38]3 years ago

6 0

Two precursor alkenes

H₃C CH₃
I I
H₂C=C-CH-CH₃ 2,3-dimethyl-1-butene

H₃C   CH₃
I   I
H₃C-CH=CH-CH₃ 2,3-dimethyl-2-butene

alkane

H₃C CH₃
  I I
H₃C-CH-CH-CH₃ 2,3-dimethylbutane

H₃C  CH₃ H₃C CH₃
I   I I I
H₂C=C-CH-CH₃ + H₂ → H₃C-CH-CH-CH₃

H₃C CH₃ H₃C   CH₃
I    I     I I
H₂C-C=CH-CH₃ + H₂ → H₃C-CH-CH-CH₃

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