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sleet_krkn [62]
3 years ago
10

An alkane with the formula C6H14 can be prepared by hydrogenation of either of two precursor alkenes having the formula C6H12.

Chemistry
2 answers:
PIT_PIT [208]3 years ago
7 0

Answer:

2-methylpentane

Explanation:

Hello,

On the attached document, you will find the solution for this exercise. It is important for you to notice that at the reactions there are two possible precursors, 2-methylpentene and 4-methylpentene which are suitable to form 2-methylpentane via hydrogenation.

Best regards.

ankoles [38]3 years ago
6 0
Two precursor alkenes

    H₃C  CH₃
         I   I
H₂C=C-CH-CH₃    2,3-dimethyl-1-butene

   H₃C      CH₃
        I       I
H₃C-CH=CH-CH₃    2,3-dimethyl-2-butene


alkane

   H₃C     CH₃
        I      I
H₃C-CH-CH-CH₃    2,3-dimethylbutane

    H₃C  CH₃                        H₃C     CH₃
         I   I                                   I      I
H₂C=C-CH-CH₃  + H₂ → H₃C-CH-CH-CH₃ 
  
    H₃C   CH₃                       H₃C     CH₃
        I    I                                   I      I
H₂C-C=CH-CH₃  + H₂ → H₃C-CH-CH-CH₃ 

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