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steposvetlana [31]
4 years ago
13

Who was charles darwin

Chemistry
2 answers:
ss7ja [257]4 years ago
7 0
Here are some facts about Charles Darwin:

.Born Feb 12, 1809
.Died April 19, 1882
.He was famous for natural selection
.He was knower as the father of evolution
.Charles Darwin Influenced the Early History of Psychology


Charles Darwin was knower for the theory of evolution about birds and natural selection he did expierment on dead birds because the same birds had a different shape of beak from each other and that's were he came up with the theory of evolution about the birds and their beaks.
Verdich [7]4 years ago
5 0
Charles Darwin was a Geologist, biologist and is best known for his contributions to science of evolution. 
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Which sequence represents the relationship between pressure and volume of an ideal gas as explained by the kinetic-molecular the
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Read 2 more answers
Why is Mm02 called manganese (IV) oxide?
Minchanka [31]

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MnO2 M n O 2 is an ionic substance without any oxo-anions, therefore its name has the -ide ending.

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3 years ago
State the phenomenon exhibited by the two atoms<br>​
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<u><em>METALS</em></u>

Lose their valence electrons easily/ ionic by electron loss.

<u><em>NOMETAL</em></u>

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6 0
2 years ago
A solution contains 0.021 M Cl and 0.017 M I. A solution containing copper (I) ions is added to selectively precipitate one of t
lidiya [134]

<u>Answer:</u> Copper (I) iodide will precipitate first.

<u>Explanation:</u>

We are given:

K_{sp} of CuCl = 1.0\times 10^{-6}

K_{sp} of CuI = 5.1\times 10^{-12}

Concentration of Cl^-\text{ ion}=0.021M

Concentration of I^-\text{ ion}=0.017M

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

  • <u>For CuCl:</u>

K_{sp}=[Cu^+][Cl^-]

Putting values in above equation, we get:

1.0\times 10^{-6}=[Cu^+]\times 0.021

[Cu^+]=\frac{1.0\times 10^{-6}}{0.021}=4.76\times 10^{-5}M

Concentration of copper (I) ion = 4.76\times 10^{-5}M

  • <u>For CuI:</u>

K_{sp}=[Cu^+][I^-]

Putting values in above equation, we get:

5.1\times 10^{-12}=[Cu^+]\times 0.017

[Cu^+]=\frac{5.1\times 10^{-12}}{0.017}=3.00\times 10^{-10}M

Concentration of copper (I) ion = 3.00\times 10^{-10}M

For the precipitation of copper (I) ions, we need less concentration of copper (I) ions. So, copper (I) iodide will precipitate first.

7 0
4 years ago
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