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Yuliya22 [10]
3 years ago
7

Chemistry: counting atoms in compounds worksheet #7.0.1 Answer please!!!!!

Chemistry
1 answer:
stealth61 [152]3 years ago
7 0
Counting atoms in a compound can be done by taking one element at a time and multiplying the subscript of the element and the number of molecules of the compounds. For example, H2O, there are two atoms of H adn 1 atom of oxygen. 
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13. Base your answer to the following question on the information below and on your knowledge of chemistry.
ahrayia [7]

From our knowledge of periodic trends, the screening effect of the inner electrons outweigh the increase in nuclear charge causing the atomic radius to increase.

<h3>Periodic trends</h3>

The periodic trends are those properties that increase or decrease down the group or across the period. These periodic trends include;

  • Ionization energy
  • Electron affinity
  • Atomic radius
  • Ionic radius etc

As more shell are added down the group in group 14, the screening effect of the inner electrons outweigh the increase in nuclear charge causing the atomic radius to increase.

Learn more about periodic trends: brainly.com/question/12074167

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2 years ago
Elements are organized on the periodic table based on their properties. Which statement correctly predicts and explains the chem
makkiz [27]
A) The alkali metal atoms forms a +1 ion, while the alkaline eaeth metal atom forms a +2 ion.
6 0
3 years ago
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How many different types of elements are there in acetone C3H6O?
Ymorist [56]

Answer:

3

Explanation:

5 0
3 years ago
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A class wants to find the ideal temperature for plants to grow in a terrarium. If the students set up several terrariums, what s
Veseljchak [2.6K]

It would be B because you want to know which TEMPERATURE is the best for the plant. Different brightness for a bulb will give different amounts of heat. Since the amount of heat is your INDEPENDENT VARIABLE, you have to change the amount of heat for each plant, so the brightness of bulbs. Therefore, B is your answer!

3 0
3 years ago
Three 5-l flasks, fixed with pressure gauges and small valves, each contains 4 g of gas at 273 k. flask a contains h2, flask b c
Varvara68 [4.7K]
First, please check the missing part in your question in the attachment.
a) So first, the Rank of pressure:
according to this formula PV = nRT and when n = m/Mw
PV = m/Mw * R*T
when we have the same mass m and the same V volume so P will proportional with the mole weight M as when the M is smaller the pressure will be greater 
when Mw of H2(A) = 2 g / Mw of He (B) = 4 g and Mw of CH4(C) = 16 g
∴ Pressure :
 (A) > (B) > (c)

B) The rank of average molecular kinetic energy:
when K = 3/2 KB T
when K is the average kinetic energy per molecule of gas 
and KB is Boltzmann's constant
and T is the temperature (K)
So from this equation, we can know that K only depends on T value, and when we have the T constant here for A, B, and C So the rank of K will be like the following:
∴ A = B = C
C) the rank of diffusion rate after the valve is opened:
according to this formula:
R2/R1 = √M1/M2
from this equation, we can see that diffusion is proportional to the reciprocal of the molecular mass M so,
when Mw H2 (A) = 2 g & Mw He(B) = 4 g & CH4 (C) = 16 g
∴ the rank of diffusion:
A > B > C

D) The rank of the Total kinetic energy of the molecules:
when we have the Mw different so it will make the no.of molecules differs as when the Mw is low the no.of molecules will be hight, and when the average molecular kinetic energy equals. so the total kinetic energy will depend on no. of molecules 
∵ Mw A < Mw B < Mw C 
∴no .of molecules of A > B >C
∴ the rank of total kinetic energy is:
A > B > C

e) the rank of density:

when ρ = m/ v 
and m is the mass & v is the volume and we have both is the same for A, B, and C
so the density also will be the same, ∴ the rank of the density is:
A = B = C

F) the rank of the collision frequency:
as the no.of molecules increase the collision frequency increase and depend also on the velocity and it's here the same.
∴ Collision frequency will only depend on the no.of molecules
we have no.of molecules of A > B > C as Mw A < B < C 
∴the rank of the collision frequency is:
A > B > C 

 



7 0
3 years ago
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