What is 7m+8=71 as a two step equation
1 answer:
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Answer:
Part A
The bearing of the point 'R' from 'S' is 225°
Part B
The bearing from R to Q is approximately 293.2°
Step-by-step explanation:
The location of the point 'Q' = 35 km due East of P
The location of the point 'S' = 15 km due West of P
The location of the 'R' = 15 km due south of 'P'
Part A
To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that =
, the right triangle ΔRPS is an isosceles right triangle
∴ ∠PRS = ∠PSR = 45°
The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°
Part B
∠PRQ = arctan(35/15) ≈ 66.8°
Therefore the bearing from R to Q = 270 + 90 - 66.8 ≈ 293.2°
Answer:
Option (4)
Step-by-step explanation:
From the graph attached,
A dotted line passes through two points (3, 1) and (-3, -3)
Let the equation of the given line is,
y = mx + b
where 'm' = slope of the line
b = y-intercept
Slope of a line passing through and
is,
m =
For the given points,
m =
m =
y-intercept 'b' = -1
Therefore, equation of the given line will be,
Since graphed line is a dotted line so it's representing an inequality(having < or > sign)
And the shaded part is below the dotted line,
Inequality will be,
y <
Therefore, Option (4) will be the answer.