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Anton [14]
3 years ago
9

Melanie needs 5,000 chocolates for an event so far she has brought 2 cases of 1,125 chocolates each how many more does she need

Mathematics
2 answers:
slava [35]3 years ago
5 0

Answer:

2750 chocolates

Step-by-step explanation:

Find how much she has bought already:

1,125(2)

= 2,250

Then, subtract this from 5,000

5000 - 2250

= 2750

So, she still needs 2750

enyata [817]3 years ago
5 0

Answer:

2,750

Step-by-step explanation:

2 cases of 1,125 chocolates = 2,250 chocolates

5,000 - 2,250 = 2,750 more chocolates needed

(that's also 3 cases of chocolates needed :p)

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If the original function () = 22 − 1 is shifted to the left 3 units to make the
Rom4ik [11]

A horizontal translation is expressed by transforming

f(x)\mapsto f(x+k)

If k is positive, the function is translated to the left. If k is negative, the function is translated to the right.

So, a 3-units left shift is given by k=3. So you have

f(x)=2x^2-1 \implies f(x+3)=2(x+3)^2-1

4 0
3 years ago
A cookout tray consists of one main item, two different sides, and a drink. if cookout offers 10 main items, 10 sides, and 5 dri
OLEGan [10]

The number of unique cookout trays are possible is 500

<h3>How many unique cookout trays are possible?</h3>

The given parameters are:

Main items = 10

Sides = 10

Drinks = 5

The number of unique cookout trays are possible is

Cookout trays = Main items * Sides * Drinks

So, we have:

Cookout trays = 10 * 10 * 5

Evaluate

Cookout trays = 500

Hence, the number of unique cookout trays are possible is 500

Read more about combination at:

brainly.com/question/11732255

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6 0
1 year ago
the volume of the stack of cubes is 176 cubic inches, which is the same as the volume found by multiplying the dimension of the
Aliun [14]

Answer:

https://campussuite-storage.s3.amazonaws.com/prod/735181/c9be791c-b8dc-11e6-bf0d-22000bd8490f/1815482/64a2070e-a58b-11e8-be02-0a844dce770e/file/Homework_Helper-Grade_5_Module_5.pdfStep-by-step explanation: sorry for the link but that should help

7 0
3 years ago
Write the number of permutations in factorial form. Then simplify. J K L M N O P
guajiro [1.7K]

Answer:

The number of permutations of the group of letters given (J, K, L, M, N, O and P) is 7! = 7 . 6 . 5 . 4 . 3 . 2 . 1 = 5,040.

Step-by-step explanation:

The number of permutations without repetition is the number of possible sequences that can occur if we take the letters one by one and is calculated with the factorial of the total number of letters in the group.

Before starting we have 7 possibilities, one for each letter. Once the first letter is chosen randomly, we will have 6 possibilities, after taking the third letter we will have 5 possibilities, and so on.

In total the total number of possibilities to obtain the 7 letters in a certain order are 7 by 6 by 5 by 4 by 3 by 2 by 1, sayed in other words factorial of 7 (7!). The result of the multiplication gives 5,040.

In short we can get the seven letters in 5,040 different sequences.

7 0
3 years ago
Which is an equivalent ratio to 7:5<br> A: 14:12<br> B:21:10<br> D:21:15
umka21 [38]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
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