Step-by-step explanation:
y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1
dy/dx = 12√x
Arc length is:
s = ∫ ds
s = ∫₀¹ √(1 + (dy/dx)²) dx
s = ∫₀¹ √(1 + (12√x)²) dx
s = ∫₀¹ √(1 + 144x) dx
If u = 1 + 144x, then du = 144 dx.
s = 1/144 ∫ √u du
s = 1/144 (⅔ u^(³/₂))
s = 1/216 u^(³/₂)
Substitute back:
s = 1/216 (1 + 144x)^(³/₂)
Evaluate between x=0 and x=1.
s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]
s = 1/216 (145)^(³/₂) − 1/216
s = (145√145 − 1) / 216
Answer:
28
Step-by-step explanation:
sorry if wrong
Answer:
37x^2+10x-28
Step-by-step explanation:
use ma.thway it will give you the answer to any math problem
Answer:
The radius is 0.398 feet to produce a perfect lawn for the lawnmower.
It is given that the width of the lawnmower is 2.5 feet and the length of the rope is 25 feet.
It is required to calculate the radius (R) of the pole that will produce a perfect lawn.
What is a circle?
It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).
We have,
Width of the lawnmower = 2.5 feet
Length of the rope = 25 feet
For the perfectly mowed lawn, it means the lawnmower width which is 2.5 feet must wrap the pole with radius R, mathematically:
The perimeter of the pole = width of the lawnmower
2πR = 2.5
R = 0.398 Feet ( π = 3.14 )
Thus, the radius is 0.398 feet to produce a perfect lawn for the lawnmower.
