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anygoal [31]
3 years ago
8

The length of the rectangle is 3 feet less than twice its width.

Mathematics
1 answer:
Contact [7]3 years ago
7 0

Answer:

I think it’s 14.5 but if I am wrong correct me plz

Step-by-step explanation:

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A new computer loses 1/2 of its value every year. Which graph could represent the relationship between the year and the computer
Igoryamba

<u>Let's first consider:</u><em> the fact that a new computer loses 1/2 of its value</em>

<em> </em>  ⇒ <u>third choice</u> and <u>fourth choice</u> are <u>eliminated</u>

    ⇒ because of the graph project the computer's value as growing over  

         years

<u>Now let's try to set up an equation</u>:

After 1st year ⇒ Computer's value = total_.value*\frac{1}{2}

After 2nd year ⇒ Computer's value = total_.value*\frac{1}{2}*\frac{1}{2}=total_.value*(\frac{1}{2}  )^2

After 3rd year ⇒ Computer's value =total_.value*\frac{1}{2}*\frac{1}{2}* \frac{1}{2}=total_.value*(\frac{1}{2})^3

     

 ..... (<em>Hopefully you see a pattern)</em>

<em />

After x year ⇒ Computer's value = total_.value*(\frac{1}{2})^x

<u>Therefore, the equation is</u>: total_.value*(\frac{1}{2})^x

  ⇒that means the graph has to <u>exponentially decreasing</u> as it has

     an exponent (<em>meaning the function is exponential</em>) and a base less

     than 1 (<em>meaning that the function is decreasing)</em>

<u>Answer: Choice (1)</u>

<u></u>

Hope that helps!

5 0
2 years ago
If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x. Consider the cost func
nadya68 [22]

Answer:

a) C(1,000)=288,491.11 $

b) c(1,000)=288.49 $/u

c) dC/dx(1,000)=349.74 $/u

d) x=100 u

e) c=220 $/u

Step-by-step explanation:

(a) Find the total cost at a production level of 1000 units.

C(x) = 2,000 + 160x + 4x^{3/2}\\\\C(1,000)=2,000 + 160(1,000) + 4(1,000)^{3/2}\\\\C(1,000)=2,000+160,000+126,491.11= 288,491.11

(b) Find the average cost at a production level of 1000 units.

c(x)=C(x)/x\\\\c(1,000)=C(1,000)/1,000=288,491.11/1,000=288.49

(c) Find the marginal cost at a production level of 1000 units.

\frac{dC}{dx} =0+160+4*(3/2)x^{3/2-1}=160+6x^{1/2}\\\\dC/dx|_{1,000}=160+6*(1,000)^{1/2}=160+189.74=349.74

(d) Find the production level that will minimize the average cost.

c=2,000x^{-1}+160+4x^{1/2}\\\\dc/dx=2,000(-1)x^{-2}+0+4(1/2)x^{-1/2}=0\\\\-2,000x^{-2}+2x^{-1/2}=0\\\\2x^{-1/2}=2,000x^{-2}\\\\x^{-1/2+2}=1,000\\\\x^{3/2}=1,000\\\\x=1,000^{2/3}=100

(e) What is the minimum average cost?

c(x) = 2,000/x + 160 + 4x^{1/2}\\\\C(100)=2,000/100 + 160 + 4(100)^{1/2}=20+160+40=220

5 0
3 years ago
What is the answer I need help
Softa [21]
Answer: A 8040 is exactly divisible by 67 the quotient is 120
3 0
2 years ago
ZABC and ZQRS are supplementary angles.
SVEN [57.7K]

THEOREM:

•<u> </u><u>Supplementary angle</u> —» The sum of two angles is equal to 180°.

ANSWER:

By supplementary angle property,

So, m∠QRS + m∠ABC = 180°

  • m∠QRS + 41° = 180°
  • m∠QRS = 180° - 41°
  • m∠QRS = 139°
3 0
3 years ago
Read 2 more answers
Jeff is 18 years older than Joe, and Jeff is also 2 1/2 times as old as Joe. How old is Joe?
Yuri [45]

7 years

First of all, half of 18 is 9, and if you divide 18 by 2.5, it results in 7.2. I hope this helps!

6 0
3 years ago
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