I will do the homework for you but is is a quiz or test I can only do if it homework
Answer:
1,211 candy bars.
Step-by-step explanation:
You divide the goal by how much the bars are selling for, or 1513.75/1.25. The answer to this is 1,211 candy bars.
Answer:
24 cm²
Step-by-step explanation:
Z zadanego powyżej pytania uzyskano następujące dane:
Obwód (obwód) = 32 cm
Wysokość (h) = 3 cm
Obszar rombu (A) =?
Następnie określimy długość boku rombu. Można to uzyskać w następujący sposób:
Obwód, czyli obwód (P) = 32 cm
Strona (y) =?
P = 4 s
32 = 4 s
Podziel obie strony przez 4
s = 32/4
s = 8 cm
Stąd długość boku rombu wynosi 8 cm
Na koniec określimy obszar rombu w następujący sposób:
Długość boków = 8 cm
Wysokość (h) = 3 cm
Obszar rombu (A) =?
A = sh
A = 8 × 3
A = 24 cm²
Dlatego obszar rombu jest
24 cm².
Answer:
4
Step-by-step explanation:
Using the normal distribution, it is found that 0.26% of the items will either weigh less than 87 grams or more than 93 grams.
In a <em>normal distribution</em> with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 90 grams, hence
.
- The standard deviation is of 1 gram, hence
.
We want to find the probability of an item <u>differing more than 3 grams from the mean</u>, hence:



The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.
- Looking at the z-table, Z = -3 has a p-value of 0.0013.
2 x 0.0013 = 0.0026
0.0026 x 100% = 0.26%
0.26% of the items will either weigh less than 87 grams or more than 93 grams.
For more on the normal distribution, you can check brainly.com/question/24663213