bearing in mind that perpendicular lines have <u>negative reciprocal</u> slopes.
now, they both intersect at 0,0, namely they both pass through it, we know the slope of the first one, so
so, we're really looking for the equation of a line whose slope is 2, and runs through (0,0).
F(x) = (x-4)(x-3)
if you put x=4, it makes f(x) 0. if you put x=3 it makes f(x) 0
Answer:
True.
Step-by-step explanation:
An Angle must be less than 90 degrees to be acute.
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].
The width of each rect. is 1/2.
The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.
The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:
{1.875, 2.5, 2.875}
Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?
