Question

-4-x^2+4x−4−x2+4x in standard form

Answer 1

Answer:

$-2x^2 + 8x - 8$

Step-by-step explanation:

To make $-4 - x^2 + 4x - 4 - x^2 + 4x$ into standard form, we want to combine like terms to get a simplified expression.

In standard form, the highest exponent term always comes first, which here is the $x^2$ term.

$-x^2 - x^2 = -2x^2$

Next comes the b term (bx).

$4x + 4x = 8x$

Then comes the constant (c).

$-4 - 4 = -8$

So in total we have $-2x^2 + 8x - 8$.

Hope this helped!