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Norma-Jean [14]
3 years ago
9

Find the slope of the line that passes through the points (−2/3, 3/4) and (5/6, −1/2).

Mathematics
1 answer:
EastWind [94]3 years ago
5 0

Answer:

-\frac{5}{6}

Step-by-step explanation:

Use the slope formula :\frac{y2-y1}{x2-x1}

-1/2 is y2, 3/4 is y1, 5/6 is x2, and -2/3 is x1.

\frac{-1/2-3/4}{5/6-(-2/3)}

\frac{-5/4}{5/6+2/3}

\frac{-5/4}{9/6}

\frac{-5}{4} ÷ \frac{9}{6}

-\frac{5}{4} • \frac{6}{9}

-\frac{5}{2} • \frac{3}{9}

-\frac{15}{18}  

-\frac{5}{6}

Hope this helps! Let me know if I got it wrong.

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How to find slope when there is the y intercept and x-intercept?
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First graph your x and y intercept then pick any two points on the line.
\frac{rise}{run} = \frac{y2 - y1}{x2 - x1}
that's the equation used to find your slope

Example:

(4,2) (8,6) let's say those are the points you pick from the line

so then you subtract 6-2=4 (6 is your y2 and 2 is your y1)

then subtracts 8-4=4 (8is your x2 and 4 is your x1)

then your left with
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if you can reduce the reduce in this case you can which leaves you with
\frac{1}{2}
and that's how you find the slope
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