The length of the rectangle is 14
<u>steps:</u>
9 + 9 = 18
46 - 18 = 28
28 ÷ 2 = 14
Answer:
-24
Step-by-step explanation:
-7 - 17 = -24.
In order to divide $306 into the ratio of 9 to 5 to 3, first you have to make each section of the ratio represented by a variable, and put it into an equation.
9x + 5x + 3x = 306
Our next step is to simplify the left side of the equation by combining all of the like terms, the ones that contain variables.
17x = 306
Finally, to solve this equation, you have to divide both sides by 17 to isolate the variable x on the left side of the equation.
x = 18
However, this is not our answer as it isn't in a ratio format and doesn't really make sense. To find our ratio, we have to multiply each of our initial numbers (9, 5, and 3) by our variable, x.
9 * 18 = 162
5 * 18 = 90
3 * 18 = 54
You can verify that these numbers are correct because if you add them together you get 306.
Your final ratio is 162:90:54.
Hope this helps! :)
If you have a separate specific question about pre-tax prices and PMed me the link, I'd be happy to help you.
The mean of 10 randomly selected students is definitely more likely to be closer to 75. 10 randomly selected students to include information and are more like to reflect the class’s scores. Consider an extreme example. Seventy-five students in a class of 100 earned perfect scores. The other 25 earned zeros. The average score of the class would be 75. A sample of 10 random students would almost certainly include more 100s then 0s, but both would be included in the sample. The mean of this samples score is closer to 75 than any individuals.
Answer:
Step-by-step explanation:
Using PEMDAS rule
Parentheses, Exponents , Multiplication, Division, Addition, Subtraction
![\sf{4 [ 3 + 3(5 - 1) ]}](https://tex.z-dn.net/?f=%20%5Csf%7B4%20%5B%203%20%2B%203%285%20-%201%29%20%5D%7D)
Subtract 1 from 5
![\longrightarrow{ \sf{4 [3 + 3 \times 4 ]}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B4%20%5B3%20%2B%203%20%5Ctimes%204%20%20%5D%7D%7D)
Multiply the numbers : 3 and 4
![\longrightarrow{ \sf{4 [ 3 + 12 ]}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B4%20%5B%203%20%2B%2012%20%20%5D%7D%7D)
Add the numbers : 3 and 12
Multiply the numbers : 4 and 15
Hope I helped!
Best regards! :D
