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2 years ago

Find the value of x in the triangle shown below. 33 103

Mathematics

1 answer:

Novay_Z [31]2 years ago

4 0

Answer:

there is no triangle.

Step-by-step explanation:

make one available

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The function y=-16x^2+36 represents the height y (in feet) of an apple x seconds after falling from a tree. Find and interpret t

Butoxors [25]

Answer:

292

Step-by-step explanation:

I don't know if it's correct but You need to learn pemdas

Btw I did this menatlly

3 0

3 years ago

What is 13 - 4x = 1 - x

JulsSmile [24]

13-4x=1-x
13=4x+x=1-x+x
13-3x=1
13-1-3x=1-1
12-3x=0
12=3x
12/3=3x/3
4=x
Therefore, x=4

5 0

3 years ago

A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.

oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

$H_0: \mu=2.4\\\\H_a:\mu> 2.4$

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58$

The degrees of freedom for this sample size are:

$df=n-1=45-1=44$

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.5801)=0.0066$

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0

3 years ago

Kiran scored 36 baskets in 1 week. She scored 1/2 of the baskets on the weekend. She scored 1/4 of them on Tuesday, she scored 1

notka56 [123]

Answer:

6 baskets did Kiran score on Thursday

Step-by-step explanation:

As per the statement:

Kiran scored 36 baskets in 1 week.

On weekend she scored = $\frac{1}{2} \cdot 36 = 18$ baskets.

She scored 1/4 of them on Tuesday

⇒On Tuesday she scored = $\frac{1}{4} \cdot 36 = 9$ baskets

She scored 1/12 of them on Wednesday

⇒On Wednesday she scored = $\frac{1}{12} \cdot 36 = 3$ baskets.

Then;

She scored = On Weekend + On Tuesday + On Wednesday = 18+9+3 = 30 baskets.

Rest on Thursday she scored = 36 - 30 = 6 baskets.

Therefore, 6 baskets did Kiran score on Thursday

8 0

3 years ago

Helppppppp! 15 points!

Vika [28.1K]

${\boxed{\mathcal{\purple{D.\:81}}}}$ ✅

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$( {3})^{ \frac{11}{5} } \div {3}^{ \frac{ - 9}{5} } \\ \\=( {3})^{ \frac{11}{5} - ( \frac{ - 9}{5} ) } \\ \\ = ( {3})^{ \frac{11}{5} + \frac{9}{5} } \\ \\ = ( {3})^{ \frac{11 + 9}{5} } \\ \\ = ( {3})^{ \frac{20}{5} } \\ \\ = ( {3})^{4} \\ \\ = ( \: 3 \times 3 \times 3 \times 3 \: ) \\ \\ = 81$

<u>Note</u>:-

${a}^{m} \div {a}^{n} = {a}^{m - n}$

$\sf\red{(-)\:x\:(-)\:=\:+}$

$\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}$

4 0

2 years ago