Answer:
x=137
y=525-137
y=388
Step-by-step explanation:
Let the student tickets be x
Let the geral Admission tickets be y
x+y=525
y=525-x
4x+6y=2876 (subsitute for y)
4x+6(525-x)=2876
4x+3150-6x=2876
-2x=-274
x=137
y=525-137
y=388
Hence, about 137 childern tickets were sold and 388 gernal admission tickets were sold.
Paul.
Given that the roots of the equation x^2-6x+c=0 are 3+8i and 3-8i, the value of c can be obtained as follows;
taking x=3+8i and substituting it in our equation we get:
(3+8i)^2-6(3+8i)+c=0
-55+48i-18-48i+c=0
collecting the like terms we get:
-55-18+48i-48i+c=0
-73+c=0
c=73
the answer is c=73
You have shared the situation (problem), except for the directions: What are you supposed to do here? I can only make a educated guesses. See below:
Note that if <span>ax^2+bx+5=0 then it appears that c = 5 (a rational number).
Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers. If this is the case, then the discriminant, b^2 - 4(a)(c), must be positive. Since c = 5,
b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.
Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then
(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,
- b plus sqrt( b^2 - 20a )
d = ------------------------------------
2a
and
</span> - b minus sqrt( b^2 - 20a )
e = ------------------------------------
2a
Some (or perhaps all) of these facts may help us find the values of "a" and "b." Before going into that, however, I'm asking you to share the rest of the problem statement. What, specificallyi, were you asked to do here?
Answer:
Step-by-step explanation:
Known facts:
- the ball dropped from a height of 64 feet
- function

First question:
- the ball hits the ground when h(t) = 0, thus we get the equation

So the ball hits the ground in 2s
Second question
- to find how long it takes the ball to fall 36 feet, we must set h(t) = 64 - 36 = 28

So the ball hits the ground in 1.5s
Hope that helps!
Answer:
use desmos. It really helps!
Step-by-step explanation: