Answer:
The primary organisms involved in the process of <u>(</u><u>b</u><u>.</u><u>)</u><u> </u><u>d</u><u>e</u><u>c</u><u>a</u><u>y</u> are bacteria and fungi.
Answer:
F (pp) = 0.04
F (Pp) = 0.32
F (PP) = 0.64
Explanation:
Studying population genetics, we used the Hardy-Weinberg equilibrium model. In the case of snails, the H-W principle predicts that the total number of cases in the population should follow the following equation: PP + 2.Pp + pp = 200.
If a population has 200 snails and 8 are affected by a recessive condition, we have 4% affected, or 0.04.
This means that 0.04 corresponds to p², and p corresponds to 0.2.
Therefore, P is equal to 0.8 because p + P = 1.
Knowing the allele frequencies, we go to the frequency of the genotypes.
F (pp) = p² = 0.04 = 8 snails
F (Pp) = 2.Pp = 0.32 = 64 snails
F (PP) = P² = 0.64 = 128 snails
Nucleotides makes up each individual strand of DNA
