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SVEN [57.7K]
3 years ago
9

M m find the value of x

Mathematics
1 answer:
Lorico [155]3 years ago
3 0
If A and J are complementary angles, that means that when they are added together, they equal 90 degrees. We can set up the equation 5x+30+4x+15=90.

5x+30+4x+15=90
9x+45=90
9x=45
x=5

:)
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Please help! I'm stuck:(
irina [24]

Answer:

1st graph is Y=1x+0

2nd Graph is Y=-2/1x + 0

Step-by-step explanation:

Your slope is 1 for the 1st graph

Your slope is -2/1 for the second graph

3 0
3 years ago
Hi please help i’ll give brainliest please
TEA [102]

Answer:

6^3=6×6×6=216. So, the answer is 6x6x6 and 216.

3 0
3 years ago
Read 2 more answers
A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions
faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that  

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

\text {Area of rectangle }=length \times width

Area of rectangular parking lot = length of rectangular parking plot \times width of the rectangular parking

\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}

But it is given that Area of rectangular parking lot = 15000 square feet

\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is  </u></em>

{ax^{2}+\mathrm{b} x+\mathrm{c}=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}

\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet  

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0
3 years ago
Smith has a garden with 40 carrots in it. They pick some carrots to feed their pet rabbit, leaving 90% of the carrots in the gar
adelina 88 [10]

Answer:the answer is 44

Step-by-step explanation: cuz  40 divided by 90%= 44

7 0
3 years ago
Read 2 more answers
Give the y-intercept of the function f(x)=x^3 + 5x^2 - 3x+3
stepladder [879]
Answer:
Y-intercept (0,-20)
3 0
3 years ago
Read 2 more answers
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