To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
Answer:

Step-by-step explanation:
Given

Required
Solve
First, convert 180lb to kg


-- to 1dp
Next, convert 12oz to kg


--- to 1 dp
So, the expression becomes:



Hence:

Answer:
B 2 < x < 6
Step-by-step explanation:
six times an integer is between 12 and 36. Between does not include so we use < not ≤
12 < 6x < 36
Divide all sides by 6
12/6 < 6x/6 < 36/6
2 < x < 6
The central angle (127 degrees) is the angle at point K
The measures of JL and JML are 127 and 233 degrees, respectively
<h3>How to determine the measures of angles JL and JML?</h3>
From the complete question, we have:
JL = 127 degrees.
The sum of angles at a point is 360 degrees
So, we have:
JML + 127 = 360
Subtract 127 from both sides
JML = 233
Hence, the measures of JL and JML are 127 and 233 degrees, respectively
Read more about circles and arcs at:
brainly.com/question/25305793