Could somebody please help explain if it would be a nonexistent or existent limit? Please answer with a simple and understandabl
e reason to why it would be a nonexistent or existent limit.
1 answer:
Answer: D
Step-by-step explanation:
For the limit as x approaches 2 from the left side, you see the point is at y=6.
For the limit as x approaches 2 from the right side, you see the point is at y=-2.
Since 6≠-2, the limit as x approaches 2 does not exist, or is nonexistent.
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Answer: x < 4-y/3
Step-by-step explanation:
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Answer:
d. 300%
Step-by-step explanation:
The given relation is ...
60%·A = 20%·B
Dividing by 20%, we see that ...
3·A = B
Of course, 3 = 3×100% = 300%, so B is 300% of A.
Answer:
10 ≤ f ( 7 ) − f ( 2 ) ≤ 15
Step-by-step explanation:
Integrating the given inequalities along the interval from x = 2 to x = 7 yields the minimum and maximum possible values:
![2 \leq f ' ( x )\leq 3\\\int\limits^7_2 {2} \, dx \leq \int\limits^7_2 {f'(x)} \, dx \leq\int\limits^7_2 {3} \, dx \\\\2*7-(2*2)\leq f(7)-f(2)\leq 3*7-(3*2)\\10\leq f(7)-f(2)\leq 15](https://tex.z-dn.net/?f=2%20%5Cleq%20f%20%27%20%28%20x%20%29%5Cleq%203%5C%5C%5Cint%5Climits%5E7_2%20%7B2%7D%20%5C%2C%20dx%20%5Cleq%20%5Cint%5Climits%5E7_2%20%7Bf%27%28x%29%7D%20%5C%2C%20dx%20%5Cleq%5Cint%5Climits%5E7_2%20%7B3%7D%20%5C%2C%20dx%20%5C%5C%5C%5C2%2A7-%282%2A2%29%5Cleq%20f%287%29-f%282%29%5Cleq%203%2A7-%283%2A2%29%5C%5C10%5Cleq%20f%287%29-f%282%29%5Cleq%2015)
The minimum possible value is 10 and the maximum possible value is 15.