Answer:
All points on line CD are equidistant from A and B
Step-by-step explanation:
Given that point A is the center of circle A and point B is the center of circle B, and the circumference of circle A passes through the center of circle B which is point B and vice versa.
Therefore we have;
The radius of circle A = The radius of circle B
Which gives;
The distance of the point C to the center A is equal to the distance of the point C to the center B
Similarly, the distance of the point D to the center A is equal to the distance of the point D to the center B
So also the distances of all points on the line from the center A is equal to the distances of all points on the line from the center B.
Answer:
Step-by-step explanation:
<u>Question 7</u>
Angle formed by 2 chords is half of the sum of the intercepted arcs
- x = 1/2(72° + 58°) = 1/2(130°) = 65°
<u>Question 8</u>
Angle formed by 2 secants is half of the difference of the intercepted arcs
- x = 1/2(360° - (130° + 98° + 41°) - 41°) = 1/2(50°) = 25°
