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Yuliya22 [10]
3 years ago
13

Point G is the center of the small circle. Point X is the center of the large circle. Points G, Y, and X are all on line segment

GX.
Marco wants to create a new circle using GX as a radius. What will be the area of Marco’s new circle?

10
16
356
676
R for GY=10
R for XY=16
Mathematics
1 answer:
kramer3 years ago
3 0

Answer:

A = 676πcm²

Step-by-step explanation:

According to given data:

GY = 10 cm

XY = 16 cm

The formula for finding the area of the circle is:

A = πr²

Since we have two radius. By adding the two radius we get:

GY+XY=10+16

=26

Now put the value in the formula:

A=πr²

A = π(26cm)²

A = 676πcm²

Thus the correct option is 676....

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200m - 100m + 48,250 = 50,250 – 150m
drek231 [11]

200m - 100m + 48,250 = 50,250 - 150m

(Add or subtract common variables)

100m + 48,250 = 50,250 - 150m

(Add 150m to both sides)

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(Divide 250 to both sides to isolate m)

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5 0
3 years ago
Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC . FIRST CORRECT ANSWER GETS POINTS AND BRAINLIEST!!!! T
Ad libitum [116K]

Answer:

Given : In △ABC, m∠A=60°, m∠C=45°,and AB=8 unit

Firstly, find the angles B

Sum of measures of the three angles of any triangle equal to the straight angle, and also expressed as 180 degree

∴m∠A+ m∠B+m∠C=180                      ......[1]

Substitute the values of m∠A=60° and m∠C=45° in [1]

60^{\circ}+ m\angle B+45^{\circ}=180^{\circ}

105^{\circ}+ m\angle B=180^{\circ}

Simplify:

m\angle B=75^{\circ}

Now, find the sides of BC

For this, we can use law of sines,

Law of sine rule is an equation relating the lengths of the sides of a triangle  to the sines of its angles.

\frac{\sin A}{BC} = \frac{\sin C}{AB}

Substitute the values of ∠A=60°, ∠C=45°,and AB=8 unit to find BC.

\frac{\sin 60^{\circ}}{BC} =\frac{\sin 45^{\circ}}{8}

then,

BC = 8 \cdot \frac{\sin 60^{\circ}}{\sin 45^{\circ}}

BC=8 \cdot \frac{0.866025405}{0.707106781} =9.798 unit

Similarly for  AC:

\frac{\sin B}{AC} = \frac{\sin C}{AB}

Substitute the values of ∠B=75°, ∠C=45°,and AB=8 unit to find AC.

\frac{\sin 75^{\circ}}{AC} =\frac{\sin 45^{\circ}}{8}

then,

AC = 8 \cdot \frac{\sin 75^{\circ}}{\sin 45^{\circ}}

AC=8 \cdot \frac{0.96592582628}{0.707106781} =10.9283 unit

To find the perimeter of triangle ABC;

Perimeter = Sum of the sides of a triangle

i,e

Perimeter of △ABC = AB+BC+AC = 8 +9.798+10.9283 = 28.726 unit.

To find the area(A) of triangle ABC ;

Use the formula:

A = \frac{1}{2} \times AB \times AC \times \sin A

Substitute the values in above formula to get area;

A=\frac{1}{2} \times 8 \times 10.9283 \times \sin 60^{\circ}

A = 4 \times 10.9283 \times 0.86602540378

Simplify:

Area of triangle ABC = 37.856 (approx) square unit





4 0
3 years ago
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