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3 years ago

How many sixteenths are equal to 5/8

Mathematics

2 answers:

Alisiya [41]3 years ago

4 0

10/16

Hope this helps you!!

mr_godi [17]3 years ago

3 0

Answer:

The answer would be 10/16.

Hope this helps!

Brianliest?

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What are the solutions of x^2 - 2x + 10 = 0?

dybincka [34]

Answer:

C. x = 1 + 3i or x = 1 - 3i

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Algebra II

Imaginary Roots: √-1 = i

Step-by-step explanation:

Step 1: Define

x² - 2x + 10 = 0

Step 2: Identify Variables

a = 1

b = -2

c = 10

Step 3: Find roots

Substitute [Quad Formula]: $x=\frac{2\pm\sqrt{(-2)^2-4(1)(10)} }{2(1)}$
Exponents: $x=\frac{2\pm\sqrt{4-4(1)(10)} }{2(1)}$
Multiply: $x=\frac{2\pm\sqrt{4-40} }{2}$
Subtract: $x=\frac{2\pm\sqrt{-36} }{2}$
Factor: $x=\frac{2\pm\sqrt{-1} \sqrt{36} }{2}$
Simplify: $x=\frac{2\pm6i }{2}$
Factor: $x=\frac{2(1\pm3i) }{2}$
Divide: $x=1\pm3i$

5 0

3 years ago

the length of one ramp is 16 feet. the vertical rise is 14 inches. estimate the ramps horizontal distance and its ramp angle. do

Paladinen [302]

The ramp's horizontal distance is the distance in the x-axis. So the ramp's vertical distance I.e y-axis is 14 inches. And its length which is actually the hypotenuse ofthe right angled triangle 16 feet. But let's convert feet to inches first. 1 feet makes 12 inches Hence 16 feet makes 192 inches. From pythagoras a^2 =b^2 + c^2 where a the hypotenuse is 192 and b is 14. C is the ramp's horizontal distance. So we have (192)^2 = (14)^2 + c^2 C^2 = 192^2 - 14^2 = 36668 C = 191.48 From SOHCAHTOA. We have to use Sin So sin theta = (14/192) Theta = sin^(-1) (14/192) = 4.1815. Yes, it meets the FAC standard since the ramp's angle is less than 4.78

3 0

4 years ago

How many cm for each please

Semenov [28]

32 3/10, 71 1/10, 73 9/10, 28 3/10, and 60

8 0

3 years ago

Find the area of the triangle using Pythagorean theorem

Furkat [3]

Answer:

Step-by-step explanation:

Remark

Use a^2 + b^2 = c^2 to solve for the height.

Givens

c = 10

b = 6

h = ?

Solution

b^2 + h^2 = c^2

6^2 + h^2 = 10^2

36 + h^2 = 100 Subtract 36

h^2 = 100 - 36

h^2 = 64 Take the square root of both sides

sqrt(h^2) = sqrt(64)

h = 8

The height = 8

Area = 1/2 * b * h

Area = 1/2 *12 * 8

Area = 48

Comment

You might wonder where the 12 came from. It wasn't given The base is the whole line across the bottom. 1/2 of it is six. The whole base = 12

6 0

3 years ago

at the beginning of grade 6 the number of advanced math to the number of regluar math students was 3:8 however after taking plac

Brut [27]

The number of students would not change between before the test and after the test. 3+8 and 4+7 both = 11 so finding out how many students would equal one ratio can then be used to find how many equal 3 and 8.

If 92 students are equal to 4 in the ratio, then 1 in the ratio is worth 23 students. This is important as then when you times 23 by 7 you find out how many students there are in the regular maths class, 161 students. Plussing these two together gives you a total of 253 students.

Using this 253 you can divide it by 11 to find out how much 1 number would be in the ratio, it equals 23. Using this you can then times 23 by both 3 and 8 to find the original class sizes, 3x23 = 69, and 23x8 = 184.

Making the origional class size of the advaced class 69 studnets, and the regular maths class size 184.

4 0

4 years ago

Read 2 more answers