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Nezavi [6.7K]
2 years ago
7

The basketball team has 48 minutes to win a game. They are on offense 18

Mathematics
1 answer:
lbvjy [14]2 years ago
6 0

Answer:

12 times

Step-by-step explanation:

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PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (80pts)
wariber [46]

Answer:

PQ = 20

QR = 15

Step-by-step explanation:

PQ^2 = 16^2 + 12^2

PQ^2 = 400

PQ = √400 = 20

QR^2 = 12^2+9^2

QR^2 = 225

QR = √225 = 15

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3 years ago
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What is the area of a rectangle with side lengths of 5/12 foot and 2/3 foot
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Step-by-step explanation:

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How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

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2 years ago
Two bicycles are driving on the circle in the same direction with speeds of 9 mph and 5 mph respectively. How many points are th
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Step-by-step explanation:

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2 years ago
Pls help me on this!
Zigmanuir [339]

Answer:

4 45/100 Keep simplifying it. You can do it!

Step-by-step explanation:

4 is the whole. 45 is out of 100

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3 years ago
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