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RSB [31]
3 years ago
15

What is 15 percent in 660

Mathematics
2 answers:
Elodia [21]3 years ago
8 0

Answer:

99

Step-by-step explanation:

10% = 66

5% = 33

66+33=99

seraphim [82]3 years ago
8 0
99 because 660/100=6.6 6.6x15
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Moving the decimal twice to the right 0.55 =
koban [17]

Answer:

55 l hope am not wrong

Step-by-step explanation:

if you find this helpful plz follow me

n mark my answer as the branliest

have a nice day/night

5 0
3 years ago
Read 2 more answers
The amount of time that people spend at Grover Hot Springs Spa is normally distributed with a mean of 63 minutes and a standard
PtichkaEL [24]

Answer:

a)X \sim N(63,18)  

Where \mu=63 and \sigma=18

b) P(X>90)=P(\frac{X-\mu}{\sigma}>\frac{90-\mu}{\sigma})=P(Z>\frac{90-63}{18})=P(Z>1.5)

And we can find this probability using the complement rule and with the normal standard table or excel:

P(Z>1.5)=1-P(Z

c) P(X

P(Z

d) P(60

P(-0.167

P(-0.167

e)  IQR = 75.13-50.87=24.26

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the amount of time that people spend at Grover Hot Springs of a population, and for this case we know the distribution for X is given by:

X \sim N(63,18)  

Where \mu=63 and \sigma=18

Part b

We are interested on this probability

P(X>90)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>90)=P(\frac{X-\mu}{\sigma}>\frac{90-\mu}{\sigma})=P(Z>\frac{90-63}{18})=P(Z>1.5)

And we can find this probability using the complement rule and with the normal standard table or excel:

P(Z>1.5)=1-P(Z

Part c

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard table or excel:

P(Z

Part d

If we apply this formula to our probability we got this:

P(60

And we can find this probability with this difference:

P(-0.167

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-0.167

Part e

Q1

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.75   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.75 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.75

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.674

And if we solve for a we got

a=63 -0.674*18=50.87

So the value of height that separates the bottom 25% of data from the top 75% is 50.87.  

Q3

Since the distribution is symmetrical we repaeat the procedure for Q1 but now with z= 0.674

z=0.674

And if we solve for a we got

a=63 +0.674*18=75.13

And then the IQR = 75.13-50.87=24.26

3 0
3 years ago
A factory has four machines that produce the same item. Machines 1 and 2 each produce 20% of the total output, while machines 3
andrezito [222]

Answer:

The answers are a. 0.27 b. 0.2 c. 0.2 d. 0.3 e. 0.3 f. 1

Step-by-step explanation:

Total output = 100% = 1

Total defective = 6% + 5% + 8% + 8% = 27% = 27

a. Prob of defective item = total defective/total output

= 27/100

= 0.27

b. Prob of defective from machine 1 = 6/27 =0.2222

~ 0.2

c. Prob of item defective from machine2 = 5/27 = 0.1852

~0.2

d. Prob of de defective from machine 3 = 8/27 = 0.2963

~0.3

e. Prob of defective from machine 4

= 8/27 = 0.2963

~ 0.3

f. Sum of prob from b-e

0.2 + 0.2 + 0.3 + 0.3

= 1

4 0
3 years ago
Solve the equation for x.
Mazyrski [523]
4x - 8 = 3x + 12
x - 8 = 12
x= 20
7 0
3 years ago
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The table below shows the number of minutes Morris practiced playing the trumpet during the past five weeks.
avanturin [10]
40-30=10
52-40=12
66-52=14
82-66=16

Each time the difference between two consective weeks gains two minutes, so if the difference between weeks 5 and 4 is =16 minutes then we add two minutes

16+2=18

Then we add the previous time to 18

18+82=100
Week 6 = 100 minutes

So the answer is A. 100
8 0
3 years ago
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