5(x – 4) + 3x – 9x = 6

BRAINLIEST TO WHOEVER CAN HELP ME !!Select the correct statement about the function represented by the table.

Paha777 [63]

B would be the answer

7 0

3 years ago

U

True [87]

Answer:

D. RWS and SWT

Step-by-step explanation:

Adjacent angles have a common side and a common vertex but they don't overlaps each other

The two angles that has these requirements are :

RWS and SWT

8 0

2 years ago

Read 2 more answers

there are five bells which ring at interval of 4,5,12 and 15 minutes respectively at what minute those bells ring at the same ti

Rus_ich [418]

<h3>Answer: 60 minutes</h3>

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Explanation:

Let's find the LCM of 4 and 5, which are the first two items of the list.

multiples of 4 are: 4,8,12,16,20,24,...
multiples of 5 are: 5,10,15,20,25,...

The smallest item in each list is 20, so the LCM of 4 and 5 is 20.

We can replace the "4,5" in the list "4,5,12,15" with "20". So our new list would be "20,12,15".

We then repeat the process of finding the LCM of the first two items

multiples of 20 are: 20,40,60,80,...
multiples of 12 are: 12,24,36,48,60,72,...

LCM of 20 and 12 is 60.

The list "20,12,15" condenses to "60,15".

Repeat this process of finding the LCM once more and you'll find the overall LCM is 60.

Therefore, the LCM of the entire set {4,5,12,15} is 60. This is the smallest multiple shared by all four values. Interestingly enough, the outer values pair up to multiply to 60, and so do the inner values.

4*15 = 60

5*12 = 60

The bells ring together every <u>60 minutes</u>

In other words, all of the bells ring together at the same time every hour (perhaps at the top of every hour; eg at 7:00 pm and at 8:00 pm, etc).

8 0

2 years ago

Three piles of 7 beans each are to be made from 10 red, 5 yellow, and 6 green beans. If all of the beans must be used and each s

Ket [755]

Answer:

The maximum number of red beans that can be put in one of the stacks is 5.

Step-by-step explanation:

First, Every pile is made with 7 beans, but they need to have at least one bean of each color, so we need to include in the pile minimum one yellow bean and one green bean. If we make a stack with this condition, the stack is going to have: 1 yellow bean, 1 green bean, and 5 red beans.

Additionally, it is necessary to know if there are enough red beans for the other piles. In this case, we have 10 red beans so if we have 5 red beans in one stack, the other two stacks have enough red beans to fulfill with the condition to have at least one red bean.

So, the maximum number of red beans that can be put in one of the stacks is 5.

7 0

3 years ago

2<br> – divide by<br> 45 how can it be simplify 2 divide by 45 <br> What could be the answer.

masya89 [10]

The only "simplify" answer would be in a decimal other than that 2 is not divisible into 45. If you can't fine a whole number that multiplied with the numerator gives you the exact number of the denominator that means that you would have to use decimals or radicals.

3 0

3 years ago

5(x – 4) + 3x – 9x = 6 - (2x + 5) + 8x