All categories

3 years ago

Which of the changes would keep the hanger in balance? Select all that apply.

Mathematics

1 answer:

Ugo [173]3 years ago

5 0

Adding to circles on the left and a square on the right.

Adding two triangles to each side.

Changes number 1 and two would keep the hanger in balance.

There you go! I really hope this helped, if there's anything just let me know! :)

You might be interested in

Maryann and Carlos are each saving for new scooters. So, far Maryann has $9 saved, and can earn $6 per hour babysitting. Carlos

tester [92]

Answer:

Step-by-step explanation:

1. !3, 1 "; { x

! 3y " 6

4x # 5y " 7 yes 2. !6, #2 "; { 3

x # 2y " 14

5x # y " 32 no

x ! 3y " 6 4x # 5y " 7 3x # 2y " 14 5x # y " 32

Solve each system by graphing. Check your answer.

3. { y " x ! 4

y " #2x ! 1 Solution: !!1, 3 " 4. { y " x ! 6

y " #3x ! 6 Solution: !0, 6 "

5. Maryann and Carlos are each saving for

new scooters. So far, Maryann has $9 saved,

and can earn $6 per hour babysitting. Carlos

has $3 saved, and can earn $9 per hour

working at his family’s restaurant. After how

many hours of work will Maryann and Carlos

have saved the same amount? What will that

amount be?

2 hours; $21

!MOUNT3AVED

5 0

3 years ago

Read 2 more answers

olga55 [171]

Answer:

$volume = \pi {r}^{2} h \\ = 3.14 \times {(2)}^{2} \times 6 \\ = 75.4 \: {cm}^{3}$

4 0

3 years ago

What type of number is 0? Rational, Irrational, Whole number, Integer

gladu [14]

It is a whole number and integer.

4 0

4 years ago

Read 2 more answers

Determine if the angles are greater than (>), less than (<), or equal (=) to each other.

Gwar [14]

Opposite side to <WYX=WX
Opposite side to <XWY=XY

Here

WX=12
XY=15

WX<XY

$\\ \sf\longmapsto$

4 0

3 years ago

Suppose a movie starts at 5:00 p.m. and Lindsay, a customer who is always late, arrives at the movie theater at a random time be

Arte-miy333 [17]

Answer:

a) We know that the distribution for X is given by: $X \sim Unif (a=10, b=45)$

The density function for this distirbution is given by:

$f(x) = \frac{1}{b-a}= \frac{1}{45-10}= \frac{1}{35} , 10 \leq X \leq 45$

So then the height of the uniform density curve would be given by:

$h = \frac{1}{35}= 0.029$

b) For this case we want to calculate the following probability:

$P(X\leq 20)$

And we can use the cumulative distribution function given by:

$F(X) =\frac{x-a}{b-a}=\frac{x-10}{35} , 10 \leq X \leq 45$

And we can calculate the probability like this:

$P(X \leq 20) = F(20) = \frac{20-10}{35}=0.286$

Step-by-step explanation:

For this case we define our random variable X="Lindsay's late arrival time, in minutes"

Part a

We know that the distribution for X is given by: $X \sim Unif (a=10, b=45)$

The density function for this distirbution is given by:

$f(x) = \frac{1}{b-a}= \frac{1}{45-10}= \frac{1}{35} , 10 \leq X \leq 45$

So then the height of the uniform density curve would be given by:

$h = \frac{1}{35}= 0.029$

Part b

For this case we want to calculate the following probability:

$P(X\leq 20)$

And we can use the cumulative distribution function given by:

$F(X) =\frac{x-a}{b-a}=\frac{x-10}{35} , 10 \leq X \leq 45$

And we can calculate the probability like this:

$P(X \leq 20) = F(20) = \frac{20-10}{35}=0.286$

7 0

4 years ago